JSON編碼問題php

Question

這種編碼方式有什麼問題？

<?php 
include ("../includes/db_con.php"); 

    $itemResults = mysql_query("SELECT `sold_for` FROM `items` WHERE `item_did_sell`='1'") or die(); 
    $mIResults = mysql_query("SELECT `mi_price`, `mi_total_sold` FROM `misc_items` WHERE `mi_total_sold`>'1'") or die(); 
    $donationResults = mysql_query("SELECT `amount` FROM `donations`") or die(mysql_error()); 

$total = 0; 
$itemTotal = 0; 
$mITotal = 0; 
$donationTotal = 0; 

while($row = mysql_fetch_assoc($itemResults)){ 
    $itemTotal += $row['sold_for']; 
    $total += $itemTotal; 
} 

while($row = mysql_fetch_assoc($mIResults)){ 
    $mITotal += ($row['mi_price'] * $row['mi_total_sold']); 
    $total += $mITotal; 
} 

while($row = mysql_fetch_assoc($donationResults)){ 
    $donationTotal += $row['amount']; 
    $total += $donationTotal; 
} 

header("Content-Type: application/json"); 
$arr = array('items' => $itemTotal,'mitems' => $mITotal,'donations' => $donationTotal,'total' => $total); 
$arr = json_encode($arr); 
echo $arr; 

include ("../includes/db_discon.php"); 
?> 

腳本輸出： {"items":1000,"mitems":0,"donations":0,"total":1000}

發生的我的客戶端的JavaScript（已認證）有在我的JSON陣列的parase錯誤。

Answer 1

http://www.jquery4u.com/json/ajaxjquery-getjson-simple/