您可以使用ROW_NUMBER()函數給每個搜索結果項目每個搜索結果中的排名:
SELECT SearchResultItemID,
SearchResultID,
Name,
Value,
RowNumber = ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID)
FROM SearchResultItem;
如果你有一個項目瞭解數字,那麼你可以使用集合函數來獲取每個名稱/值對:
WITH RankedItem AS
( SELECT SearchResultItemID,
SearchResultID,
Name,
Value,
RowNumber = ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID)
FROM SearchResultItem
)
SELECT SearchResultID,
Name1 = MIN(CASE WHEN RowNumber = 1 THEN Name END),
Value1 = MIN(CASE WHEN RowNumber = 1 then Value END),
Name2 = MIN(CASE WHEN RowNumber = 2 THEN Name END),
Value2 = MIN(CASE WHEN RowNumber = 2 then Value END),
Name3 = MIN(CASE WHEN RowNumber = 3 THEN Name END),
Value3 = MIN(CASE WHEN RowNumber = 3 then Value END),
Name4 = MIN(CASE WHEN RowNumber = 4 THEN Name END),
Value5 = MIN(CASE WHEN RowNumber = 4 then Value END)
FROM RankedItem
GROUP BY SearchResultID;
然後,您可以加入這個回到您的搜索結果表g艾爾文一個完整的查詢:
WITH RankedItem AS
( SELECT SearchResultItemID,
SearchResultID,
Name,
Value,
RowNumber = ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID)
FROM SearchResultItem
), Items AS
( SELECT SearchResultID,
Name1 = MIN(CASE WHEN RowNumber = 1 THEN Name END),
Value1 = MIN(CASE WHEN RowNumber = 1 then Value END),
Name2 = MIN(CASE WHEN RowNumber = 2 THEN Name END),
Value2 = MIN(CASE WHEN RowNumber = 2 then Value END),
Name3 = MIN(CASE WHEN RowNumber = 3 THEN Name END),
Value3 = MIN(CASE WHEN RowNumber = 3 then Value END),
Name4 = MIN(CASE WHEN RowNumber = 4 THEN Name END),
Value4 = MIN(CASE WHEN RowNumber = 4 then Value END)
FROM RankedItem
GROUP BY SearchResultID
)
SELECT SearchResult.SearchResultID,
SearchResult.ProductID,
SearchResult.SearchQuery,
SearchResult.WebsiteName,
SearchResult.URL,
SearchResult.IsFound,
SearchResult.CreatedOn,
SearchResult.BatchID,
SearchResult.Name,
Items.Name1,
Items.Value1,
Items.Name2,
Items.Value2,
Items.Name3,
Items.Value3,
Items.Name4,
Items.Value4
FROM SearchResult
INNER JOIN Items
ON SearchResult.SearchResultID = Items.SearchResultID;
Example on SQL Fiddle
如果你想返回一個可變數量的值,那麼你就需要使用動態SQL:
DECLARE @SQL NVARCHAR(MAX) = '';
SELECT @SQL = @SQL + ',[Name' + rn + '], [Value' + rn + '] '
FROM ( SELECT DISTINCT
rn = CAST(ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID) AS VARCHAR)
FROM SearchResultItem
) p;
SET @SQL = 'WITH RankedItem AS
( SELECT SearchResultItemID,
SearchResultID,
Name,
Value,
RowNumber = ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID)
FROM SearchResultItem
), UnPivoted AS
( SELECT upvt.SearchResultID,
Name = upvt.n + CAST(RowNumber AS VARCHAR),
upvt.v
FROM RankedItem
UNPIVOT
( n
FOR v IN ([Name], [Value])
) upvt
), Pivoted AS
( SELECT *
FROM UnPivoted
PIVOT
( MAX(V)
FOR Name IN (' + STUFF(@SQL, 1, 1, '') + ')
) pvt
)
SELECT SearchResult.SearchResultID,
SearchResult.ProductID,
SearchResult.SearchQuery,
SearchResult.WebsiteName,
SearchResult.URL,
SearchResult.IsFound,
SearchResult.CreatedOn,
SearchResult.BatchID,
SearchResult.Name' + @SQL + '
FROM SearchResult
INNER JOIN Pivoted
ON SearchResult.SearchResultID = Pivoted.SearchResultID;';
EXECUTE SP_EXECUTESQL @SQL;
Example on SQL Fiddle
NB我有意使用一種不同的方法在動態sql中做這件事,只是爲了顯示有多種方式來實現組合行的結果。
有很多方法可以做到這一點。你知道你有多少結果嗎?你想把每行的信息連接在一起成一列還是你想爲每一行分開一列? –
Hi @DavidSöderlund,理想情況下,我想爲每一行分開一列,我也可以事先知道我需要的結果數量,例如,我知道這個查詢將有3組名/值.. – 109221793