2009-09-11 37 views
5

我想模擬許多按鍵事件。我使用XTestFakeKeyEvent找到了一個解決方案,但是當我模擬超過210次時,我的程序引發了「達到的最大客戶端數量」分段錯誤。我不知道如何解決這個問題。幫助:達到客戶端的最大數量 - 分段錯誤

我的代碼在這裏:

#include <X11/Xlib.h> 
#include <X11/keysym.h> 
#include <X11/extensions/XTest.h> 
#include <stdio.h> 

#define PRESS_UP 0 
#define PRESS_DOWN 1 
#define PRESS_LEFT 2 
#define PRESS_RIGHT 3 
#define PRESS_ENTER 4 
#define PRESS_ESC 5 
#define PRESS_HOME 6 

Display *display; 
unsigned int keycode; 

int press(int key){ 
    display = XOpenDisplay(NULL); 

    if(key == PRESS_UP) 
     keycode = XKeysymToKeycode(display, XK_Up); 
    else if(key == PRESS_DOWN) 
     keycode = XKeysymToKeycode(display, XK_Down); 
    else if(key == PRESS_LEFT) 
     keycode = XKeysymToKeycode(display, XK_Left); 
    else if(key == PRESS_RIGHT) 
     keycode = XKeysymToKeycode(display, XK_Right); 
    else if(key == PRESS_ENTER) 
     keycode = XKeysymToKeycode(display, XK_Return); 
    else if(key == PRESS_ESC) 
     keycode = XKeysymToKeycode(display, XK_Escape); 
    else if(key == PRESS_HOME) 
     keycode = XKeysymToKeycode(display, XK_Home); 

    XTestFakeKeyEvent(display, keycode, True, 0); 
    XTestFakeKeyEvent(display, keycode, False, 0); 
    XFlush(display); 
    return 0; 
} 

int main(int argc, char *argv[]){ 
    int count = 0; 
    while (count < 500){ 
     press(PRESS_UP); 
     printf("count =%d\n" ,count); 
     count ++; 
    } 
} 

輸出:

$ gcc -lXtst -lX11 Util_KeyPressSimulator.c 
$ ./a.out 
count =0 
^[[Acount =1 
^[[Acount =2 
... 
^[[Acount =208 
^[[Acount =209 
^[[Acount =210 
^[[AMaximum number of clients reachedSegmentation fault 

難道一個請幫忙,謝謝。

回答

12

你在做一個XOpenDisplay每迭代沒有匹配XCloseDisplay。考慮在循環之外打開顯示屏main()一次,然後在退出之前將其關閉。

+2

也沒有檢查失敗的'XOpenDisplay',所以如果失敗,那麼這個客戶端崩潰。 – mark4o 2009-09-11 19:18:08