max（）的價值從嵌套選擇沒有ORDER BY

Question

這個問題，我發現是驅使我堅果，（編輯:)，因爲我試圖達到這個沒有順序的方法。 我有一個表：

BookAuthors（書作者）

book  author 
------ --------- 
1  Joy McBean 
2  Marti McFly 
2  Joahnn Strauss 
2  Steven Spoilberg 
1  Quentin Toronto 
3  Dr E. Brown 

兩個，書籍和作家，是關鍵。

現在我想選擇不同「作者」的最高數量和作者數量的「書」值。 在我們的例子中，查詢應該檢索3本作者的'book'2。

book  authors 
-------- ------------ 
2   3 

我已經能夠將它們分組，並獲得作家的數量爲每本書與此查詢：

select B.book, count(B.author) as authors 
from BookAuthors B 
group by B.book 

這將導致：

book  authors 
-------- ------------- 
1    2 
2    3 
3    1 

現在我只想獲得作者人數最多的書。 這是我試過的一個查詢：

select Na.libro, Na.authors from (
    select B.book, count(B.author) as authors 
    from BookAuthors B 
    group by B.book 
    ) as Na 
where Na.authors in (select max(authors) from Na) 

和

select Na.libro, Na.authors from (
    select B.book, count(B.author) as authors 
    from BookAuthors B 
    group by B.book 
    ) as Na 
having max(Na.authors) 

我有點掙扎......

謝謝您的幫助。

編輯： 因爲@Sebas是那種答辯權和擴大我的問題，這裏是解決方案使用CREATE VIEW方法來我的腦海：

create view auth as 
    select A.book, count(A.author) 
    from BooksAuthors A 
    group by A.book 
; 

然後

select B.book, B.nAuthors 
from auth B 
where B.nAuthors = (select max(nAuthors) 
        from auth) 

Answer 1

SELECT cnt.book, maxauth.mx 
FROM (
    SELECT MAX(authors) as mx 
    FROM 
     (
      SELECT book, COUNT(author) AS authors 
      FROM BookAuthors 
      GROUP BY book 
     ) t 
    ) maxauth JOIN 
     (
      SELECT book, COUNT(author) AS authors 
      FROM BookAuthors 
      GROUP BY book 
     ) cnt ON cnt.authors = maxauth.mx 

這種解決方案會更美觀高效，以期：

CREATE VIEW v_book_author_count AS 
    SELECT book, COUNT(author) AS authors 
    FROM BookAuthors 
    GROUP BY book 
; 

然後：

SELECT cnt.book, maxauth.mx 
FROM (
    SELECT MAX(authors) as mx 
    FROM v_book_author_count 
    ) maxauth JOIN v_book_author_count AS cnt ON cnt.authors = maxauth.mx 
; 

Answer 2

select book, max(authors) 
from (select B.book, count(B.author) as authors 
    from BookAuthors B group by B.book) 
table1; 

我無法嘗試這個，因爲我沒有與我的MySQL ...你試着讓我知道...

Answer 3

SELECT book b, COUNT(author) c 
FROM BookAuthors 
GROUP BY b 
ORDER BY c DESC LIMIT 1;