如何在多個查詢中進行多個字符串替換？

Question

我有一個名爲$queries一個數組，看起來像這樣：

Array ( 
    [0] => SELECT * FROM StudentRecord WHERE Year = '%YEAR%' AND Session = '%SESSION%' AND StudentID = '%SID%'; 
    [1] => SELECT * FROM Student_ApplicationRecord WHERE ApplicationYear = '%YEAR%' AND Session%SESSION% = 1; 
) 

我也有一個第二陣列稱爲$variables，看起來像這樣：

$variables = array('YEAR' => 2016, 'SESSION' => 1, 'SID' => $_SESSION['sid']); 

我想用替換$queries變量正確的值在$variables。

我已經嘗試了許多解決方案，我已經拿出了迄今爲止最好的是：

foreach ($queries as $query) 
    foreach($variables as $key=>$value) 
     $newqueries[] = str_replace("%".$key."%", $value, $query); 

然而這僅僅是在每個查詢一次更換一個變量。

即當我這樣做：

foreach ($newqueries as $query) 
    print ($query); 

每個查詢的結果是：

SELECT * FROM StudentRecord 
WHERE Year = '%YEAR%' AND Session = '%SESSION%' AND SID = '%SID%'; 

SELECT * FROM StudentRecord 
WHERE Year = '%YEAR%' AND Session = '1' AND SID = '%SID%'; 

SELECT * FROM StudentRecord 
WHERE Year = '%YEAR%' AND Session = '%SESSION%' AND SID = '1234'; 

我要的是一個最終的陣列$newqueries，看起來像這樣：

Array ( 
    [0] => SELECT * FROM StudentRecord WHERE Year = '2016' AND Session = '1' AND StudentID = '1234'; 
    [1] => SELECT * FROM Student_ApplicationRecord WHERE ApplicationYear = '2016' AND Session1 = 1; 
) 

任何人都可以幫我嗎？我很抱歉，如果之前已經問過這個問題，但我還沒有找到任何類似的問題。

Answer 1

由於str_replace()接受您可以使用該參數的$search和$replace參數的數組。

$search = ['%YEAR%', '%SESSION%', '%SID%']; 
$replace = ['2016', '1', $_SESSION['id']]; 
$newQueries = []; 
foreach ($queries as $query) { 
    $newQueries[] = str_replace($search, $replace, $query); 
}