我很JavaScript新手, 有關於在JavaScript中數組的一個問題。 單刀直入: 我的HTML代碼:結合從SQL查詢和javascript結果計算領域
<input type="text" name="conPrice" id="conPrice" size="16" maxlength="128"/>
<input type="text" name="OverP" id="OverP" size="16" maxlength="128" />
<div id="slider"></div> //Slider
第一場的數量,即從滑塊拉到。 從SQL表價格第二場
SQL是基於一個條件,有四個方面:
| ID | MIN | MAX | PRICE |
我試圖得到一個價格列價格領域OverP這取決於我的滑塊價值是。因此,例如,如果我有一個滑塊6號,這是1-7 MIN和MAX之間,這樣的價格是10
我有這樣的SQL:
<?php
$x = mysql_query("SELECT p_max AS max FROM dsd_price");
$y = mysql_query("SELECT p_min AS min FROM dsd_price");
$z = mysql_query("SELECT p_price AS price FROM dsd_price");
while ($x_array = mysql_fetch_array($x)){$max[] = $x_array;}
while ($y_array = mysql_fetch_array($y)){$min[] = $y_array;}
while ($z_array = mysql_fetch_array($z)){$price[] = $z_array;}
?>
最後我JS:
<script>
$(document).ready(function slider() {
$("#slider").slider({
value:1,
min: 0,
max: 201,
step: 1,
slide: function(event, ui) {
//Its setting the slider value to the element with id "conPrice"
$("#conPrice").val(ui.value);
}
});
});
$(document).ready(function calcul() {
var frm = document.dsd_form;
var quant = frm.conPrice;
var overp = ['<?php echo implode("','", $price); ?>'];
var mini = ['<?php echo implode("','", $min); ?>'];
var maxi = ['<?php echo implode("','", $max); ?>'];
for(index = 0; quant > mini[index], quant < maxi[index]; index++){
$("#OverP").val(overp[index]);
})
}
</script>
,我沒有得到一個結果,我想,我知道這個問題是我的JS。 希望儘快爲我的話題提出一些建議。
UPDATE: 測試頁的整個代碼把爲止。滑蓋滑呢,滑塊值正在處理conPrice,但計算不工作...
<script src="jquery.js" type="text/javascript" charset="utf-8"></script>
<!-- For slider -->
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/jquery-ui.min.js"></script>
<!-- Slider JS -->
<?php
$x = mysql_query("SELECT p_max AS max FROM dsd_price");
$y = mysql_query("SELECT p_min AS min FROM dsd_price");
$z = mysql_query("SELECT p_price AS price FROM dsd_price");
while ($x_array = mysql_fetch_array($x)){$max[] = $x_array['max'];}
while ($y_array = mysql_fetch_array($y)){$min[] = $y_array['min'];}
while ($z_array = mysql_fetch_array($z)){$price[] = $z_array['price'];}
?>
<script>
$(document).ready(function slider() {
$("#slider").slider({
value:1,
min: 0,
max: 201,
step: 1,
slide: function(event, ui) {
//Its setting the slider value to the element with id "conPrice"
$("#conPrice").val(ui.value);
}
});
function price(){
var frm = document.dsd_form;
var quant = frm.conPrice;
var overp = ['<?php echo implode("','", $price); ?>'];
var mini = ['<?php echo implode("','", $min); ?>'];
var maxi = ['<?php echo implode("','", $max); ?>'];
for(var index = 0; quant > mini[index], quant < maxi[index]; index++){
$("#OverP").val(overp[index]);
}
}
});
</script>
</head>
<body>
<form id="dsd_form" name="dsd_form" action="db_create_sql.php" method="post" class="niceform">
<fieldset>
<dl>
<dt><label for="conPrice">Price:</label></dt>
<dd><input type="text" name="conPrice" id="conPrice" size="16" maxlength="128" />
<input type="text" name="OverP" id="OverP" size="16" maxlength="128" />
<div id="slider" ></div>
</dd>
</dl>
</fieldset>
</form>
</body>
</html>
有SQL數據庫:
p_id | p_min | p_max | p_price
1 1 1 11
2 2 5 13
你得到什麼結果呢? –
到目前爲止,我沒有收到任何消息,因爲JS的最後一部分肯定有錯誤。如果我會拿出部分開始以$(文件)。就緒(函數演算(){ 它給我滑塊和數字輸出conPrice –
使用的瀏覽器工具嘗試,如螢火蟲(火狐)或Chrome的開發工具(F12打開它),它會顯示任何JS錯誤 –