插入到相同的表,我有:如何從表複製下表記錄和使用存儲過程的SQL Server
我只想複製那些從0版本記錄及其student_id數據是永遠在版本1中重複,這意味着不變的記錄。我想將所有複製的記錄插入到版本爲1的同一張表。什麼是存儲過程。
插入到相同的表,我有:如何從表複製下表記錄和使用存儲過程的SQL Server
我只想複製那些從0版本記錄及其student_id數據是永遠在版本1中重複,這意味着不變的記錄。我想將所有複製的記錄插入到版本爲1的同一張表。什麼是存儲過程。
您可以通過執行選擇記錄:
select t.*
from t
where t.version = 0 and
not exists (select 1
from t t2
where t2.student_id = t.student_id and t2.version = 1
);
剩下的只是一個insert
。
使用group by
和having max(version) = 0
:
insert into student_name (student_id, student_name, version)
select student_id, max(student_name), 1
from student_name
group by student_id
having max(version) = 0
被存儲的過程中,採取了version
一個參數,即插入了學生沒有該版本記錄誰記錄:輸出行是插入:
create procedure dbo.insert_new_version (@version int) as
begin;
set nocount, xact_abort on;
insert into student_name (student_id, student_name, version)
output inserted.*
select
student_id
, student_name = max(student_name)
, version = @version
from student_name
group by student_id
having max(version) < @version
end;
rextester演示:http://rextester.com/JSTNI40605
個回報:
+-----------+------------+--------------+---------+
| record_id | student_id | student_name | version |
+-----------+------------+--------------+---------+
| 11 | 3 | ccc | 1 |
+-----------+------------+--------------+---------+
您可以選擇和插入這樣
Insert INTO tableName select t1.student_Id, t1.student_name,1 from tablename t1
where t1.version = 0 and not exists
(select 1 from tablename t2 where t2.student_id = t.student_id and t2.version = 1);
雖然這段代碼可能會回答這個問題,但應該總是解釋它的作用以及它如何解決問題。 – BDL
您可以通過LEFT試試這個加入:
INSERT INTO TBL SELECT T1.record_id,T1.student_Id ,T1.student_name,1 FROM tbl T1 LEFT JOIN tbl T2 ON T1.student_Id = T2.student_Id AND T2.version = 1 WHERE T1.version = 0 AND T2.record_id IS NULL
我建議使用while循環遍歷表並確定需要複製的項目,然後對這些值進行 評估,如果它們符合重新插入的標準並且然後插入它們。
您的代碼應該如下所示。添加CREATE PROC部分,編輯表名適用 (警告:我寫了這對記事本,所以如果你得到了一些錯誤,只是嘗試解決這些問題)
DECLARE @counter int = 0, @row_Count int = 0, @currentId int,
@currentName nvarchar(100), @version int, @current_Student_id int
SET @row_Count = (SELECT COUNT(record_Id) from yourTable)
WHILE @counter <= @row_Count
BEGIN
SET @currentId = (SELECT record_Id FROM (SELECT row_number() over (order by id)
AS RowNum, record_Id FROM yourTable) sub WHERE [email protected])
SET @currentName = (SELECT student_name FROM yourTable WHERE record_Id = @currentId)
SET @current_Student_id = (SELECT student_id FROM yourTable WHERE record_Id = @currentId)
SET @version = (SELECT version FROM yourTable WHERE record_Id = @currentId)
--USE IF to check if the current version is 0 and the student ID has not been inserted already
IF (SELECT COUNT(record_Id) FROM yourTable WHERE student_id = @current_Student_id AND version = 1) < 1
AND @version = 0
BEGIN
INSERT INTO yourTable (student_id, student_name, version)
VALUES
(
@current_Student_id,
@currentName,
1
)
END
SET @counter = @counter + 1;
END
問:「什麼會被存儲過程本」。答:「存儲過程將是可能的解決方案之一。」但非常嚴肅的是,你必須告訴我們你曾經嘗試過什麼,不要指望得到任何答案。 –