PHP/MySQL的分頁參數無效

Question

後DB連接 -

`$tbl_name="mytable";` 
$adjacents = 3; 
$query = "SELECT COUNT (*) as num FROM $mytable"; 
$total_pages = mysql_fetch_array(mysql_query($query)); this is line 32 
$total_pages = $total_pages[num]; 
$targetpage = "pagination.php"; (the name of this file) 
$limit = 20; 

錯誤我收到IS-

警告：mysql_fetch_array（）：提供的參數是不符合一個有效的MySQL結果資源32.

任何人都可以幫忙嗎？

感謝

Answer 1

的問題應該是在查詢中，它應該是：

$query = "SELECT COUNT (*) as num FROM mytable"; 

或

$query = "SELECT COUNT (*) as num FROM ".$tbl_name.""; 

你引用你以前沒有一個變量$ MYTABLE定義爲