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我無法理解第二個函數引發的錯誤。當我通過第二功能黑客我實現打印(X)給我: [ '安娜',74.0],[ '比爾',65.0],[ 'CAL',98.0] 無列表錯誤後的無類型
由於到這個沒有,我無法遍歷列表並將其設置爲L.什麼導致這沒有?這是另外3個功能的粘貼箱。 code here!。任何意見或推動正確的方向非常感謝。
def string_avg(L):
'''(list of str) -> list of list
Given a list of strings where each string has the format:
'name, grade, grade, grade, ...' return a new list of
lists where each inner list has the format :
[name (str), average grade (float)]
Requirement: This function should be 1 line long.
>>> string_avg(['Anna, 50, 92, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5,
98'])
[['Anna', 74.0], ['Bill', 65.0], ['Cal', 98.0]]
'''
return(average_grade((string_list(L))))
def string_avg_update(L):
'''(list of str) -> NoneType
Given a list of strings where each string has the format:
'name, grade, grade, grade, ...' update the given
list of strs to be a list of floats where each item
is the average of the corresponding numbers in the
string. Note this function does NOT RETURN the list.
>>> L = ['Anna, 50, 92, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5, 98']
>>> string_avg_update(L)
>>> L
[74.0, 65.0, 98.0]
'''
x = string_avg(L)
我打算代碼的最後一個函數是:
Say I changed the last function code to:
x = string_avg(L)
for i in range(0,len(x)):
L[i] = x[i][1]
但它說我找不到nonetype的LEN,爲什麼我的X一無類型?
假如你運行你寫到文檔的文檔測試?結果是什麼? –
'x = string_avg(L)'設置一個局部變量'x',當函數結束時這個變量不會被使用。 –
@MichaelButscher我得到了['安娜,50,92,80','比爾,60,70','Cal,98.5,100,95.5,98']回到我的第二個功能(這與輸入)以及所有其他功能的預期結果。我的目標是找出什麼導致沒有,然後設置L [每個索引] = x [每個索引] [1]。 –