2014-01-15 75 views
5

Hibernate的標準,我有我的實體:與EmbeddedId

@Entity 
@Table(name="performances") 
@AssociationOverrides({ 
    @AssociationOverride(name="id.player", [email protected](name="player_id")), 
    @AssociationOverride(name="id.season", [email protected](name="season_id")) 
}) 
public class Performance extends AbstractEntity<PerformanceID> { 

    private static final long serialVersionUID = 1L; 

    @EmbeddedId 
    @Getter @Setter 
    private PerformanceID id; 
    @Getter @Setter 
    private int goals; 

    public Player getPlayer(){ 
     return id.getPlayer(); 
    } 

    public Season getSeason(){ 
     return id.getSeason(); 
    } 

和:

@Embeddable 
public class PerformanceID implements Serializable { 

    private static final long serialVersionUID = 1L; 

    @ManyToOne(fetch=FetchType.LAZY, targetEntity=Player.class) 
    @JoinColumn(name="player_id") 
    @Getter @Setter 
    private Player player; 
    @ManyToOne(fetch=FetchType.LAZY, targetEntity=Season.class) 
    @JoinColumn(name="season_id") 
    @Getter @Setter 
    private Season season; 

如何選擇業績記錄,其中玩家們的名字 '克勞迪奧'?在HQL它只是工作:

Query query = getSession().createQuery("from Performance where id.player.name = 'Claudio'"); 
return query.list(); 

但我需要這樣做的Criteria API。下面的代碼將失敗:

Criteria criteria = getSession().createCriteria(Performance.class); 
criteria.add(Restrictions.ilike("id.player.name", "Claudio")); 
return criteria.list(); 

org.hibernate.QueryException:在 org.hibernate.persister pl.andrzejcichon.criterionlazydatamodel.entities.Performance:無法解析屬性:的 id.player.name .entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:83) 在 org.hibernate.persister.entity.AbstractPropertyMapping.toColumns(AbstractPropertyMapping.java:98) 在 org.hibernate.persister.entity.BasicEntityPropertyMapping.toColumns(BasicEntityPropertyMapping .java:61) 在 org.hibernate.persister.entity.AbstractEntityPersister.toColumns(AbstractEntityPersister.java:1912) 在 org.hibernate.loader.criteria.CriteriaQueryTranslator.getColumns(CriteriaQueryTranslator.java:523) 在 org.hibernate.loader .criteria.CriteriaQueryTranslator.findColumns(CriteriaQueryTranslator.java:538) 在 org.hibernate.criterion.LikeExpression.toSqlString(LikeExpression.java:80) 在 org.hibernate.loader.criteria.CriteriaQueryTranslator.getWhereCondition(CriteriaQueryTranslator.java :419) at org.hibernate.loader.criteria.CriteriaJoinWalker。(CriteriaJoinWalker.java:123) at org.hibernate.loader.criteria.CriteriaJoinWalker。(CriteriaJoinWalker.java:92) at org.hibernate.loader.criteria.CriteriaLoader。(CriteriaLoader.java:93) at org.hibernate.internal.SessionImpl.list( SessionImpl.java:1599)在 org.hibernate.internal.CriteriaImpl.list(CriteriaImpl.java:374)在 pl.andrzejcichon.criterionlazydatamodel.repository.impl.PerformanceDatabaseRepository.customList(PerformanceDatabaseRepository.java:29) 在 PL .andrzejcichon.criterionlazydatamodel.repository.impl.PerformanceDatabaseRepositoryTest.test(PerformanceDatabaseRepositoryTest.java:24) 在sun.reflect.NativeMethodAccessorImpl.invoke0(本機方法)維持在01 sun.reflect.NativeMethodAccessorImpl.invoke(來源不明)sun.reflect.DelegatingMethodAccessorImpl.invoke(來源不明)在 java.lang.reflect.Method.invoke(來源不明)在 org.junit.runners.model.FrameworkMethod $ 1.runReflectiveCall(FrameworkMethod.java:45) 在 org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) 在 org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:42) 在 org.junit.internal .runners.statements.InvokeMethod.evaluate在 org.springframework.test.context.junit4.statements.RunBeforeTestMethodCallbacks.evaluate(RunBeforeTestMethodCallbacks.java:74)(InvokeMethod.java:20) 在 org.springframework.test.context.junit4.statements。RunAfterTestMethodCallbacks.evaluate(RunAfterTestMethodCallbacks.java:83) 在 org.springframework.test.context.junit4.statements.SpringRepeat.evaluate(SpringRepeat.java:72) 在 org.springframework.test.context.junit4.SpringJUnit4ClassRunner。 runChild(SpringJUnit4ClassRunner.java:231) 在 org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:47) 在org.junit.runners.ParentRunner $ 3.run(ParentRunner.java:231)在 組織。 org.junit.runners.ParentRunner.runChildren(ParentRunner.java:229)at org.junit.runners.ParentRunner.access $ 000(ParentRunner.java: 50)at org.jun it.runners.ParentRunner $ 2.evaluate(ParentRunner.java:222)在 org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61) 在 org.springframework.test.context。 junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:71) at org.junit.runners.ParentRunner.run(ParentRunner.java:300)at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner。的java:174) 在 org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50) 在 org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution。 java:38) at 個org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) 在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) 在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390) 在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)

其他嘗試:

Criteria criteria = createCriteria(); 
criteria.createAlias("id.player", "player"); 
criteria.add(Restrictions.ilike("player.name", "Claudio")); 
return criteria.list(); 

會生成查詢:

休眠:選擇this_.player_id爲player2_1_0_,this_.season_id爲 season3_1_0_,this_.goals作爲goals1_0_從表演THIS_其中 player1_.name ILIKE?

但它會失敗,並SQLGrammarException:「缺少從表player1_條款」

回答

0

你的映射是不正確。一個EmbeddableId類應該包含@Id(因此Serializable)值,而不是映射或複雜類型。你應該將你的映射移動到你的實體類中,然後只在EmbbedableId類中包含它們的id。請看下面的例子(從JPA 2.2規範)

@Embeddable 
public class DependentId { 
    String name; 
    long empPK; // corresponds to PK type of Employee 
} 

@Entity 
public class Dependent { 
    @EmbeddedId DependentId id; 

    // id attribute mapped by join column default 
    @MapsId("empPK") // maps empPK attribute of embedded id 
    @ManyToOne Employee emp; 
}