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好的,所以我在下面的短腳本中解決了一些錯誤。未捕獲錯誤:無法讀取null的屬性'top'
這裏你可以看到一個工作演示:http://jsfiddle.net/XG24G/2/
對不起,這裏給出這樣一個廣闊的範圍內,但是當我從JSFiddle.net到例如下面的代碼插入代碼段,我的JavaScript控制檯給我一個Uncaught TypeError: Cannot read property 'top' of null
。奇怪的是,當檢查我上面發佈的JSFiddle示例的控制檯時,此錯誤不存在。
這裏是我的javascript(用於垃圾郵件再次抱歉,但我需要顯示完整的上下文這裏):
編輯:我曾在這裏之前粘貼代碼錯誤,我現在已經修好了
$(window).scroll(function(){
// gets the position of the window
var y = $(window).scrollTop();
$(".popup_next").each(function() {
var $parentOffset = $(this).parent('article').offset().top;
var $hideOffset = $parentOffset + 30;
if(y > ($parentOffset) && y < ($hideOffset)) {
$(this).fadeIn('350');}
if(y > ($hideOffset)) {
$(this).fadeOut('500');}
if(y < ($parentOffset)) {
$(this).fadeOut('500');}
});
// for .popup_01 div
// fades a div in if it's within the scroll range and then back out if it's not
if(y > (2460) && y < (2650)){
$(".popup_01").fadeIn('350');}
if(y > (2650)){
$(".popup_01").fadeOut('500');}
if(y < (2460)){
$(".popup_01").fadeOut('500');}
// for .popup_02 div
// fades a div in if it's within the scroll range and then back out if it's not
if(y > (2750) && y < (3050)){
$(".popup_02").fadeIn('350');}
if(y > (3050)){
$(".popup_02").fadeOut('500');}
if(y < (2750)){
$(".popup_02").fadeOut('500');}
// for .popup_03 div
// fades a div in if it's within the scroll range and then back out if it's not
if(y > (5878) && y < (6378)){
$(".popup_03").fadeIn('350');}
if(y > (6378)){
$(".popup_03").fadeOut('500');}
if(y < (5878)){
$(".popup_03").fadeOut('500');}
});
// invoke jQuery.parallax-1.1.js and call related variables
//.moveRelative() options:
//x position
//adjuster (y position to start from)
//inertia (speed to move relative to vertical scroll)
//outerHeight (true/false)
$('#first').moveRelative("50%", 742, 0.05, true);
$('#first .grid').moveRelative("50%", 742, 0.8, true);
$('#third').moveRelative("50%", 4700, 0.08, true);
$('#fourth').moveRelative("50%", 5550, 0.08, true);
$('#fourth .overlay').moveRelative("50%", 5550, 0.14, true);
$('#fifth').moveRelative("50%", 7300, 0.4, true);
$('#sixth').moveRelative("50%", 7800, 0.2, true);
$('#sixth .grid').moveRelative("50%", 0, 0.8, true);
// echo useragent string inside html element - useful for specific targeting of modern browsers
var b = document.documentElement;
b.setAttribute('data-useragent', navigator.userAgent);
b.setAttribute('data-platform', navigator.platform);
,這裏是我的HTML
<article class="section" id="second">
<div id="hannah_bg">
<div class="popup popup_next popup_second"><div class="inner">
<a class="scroll" href="#third">⇓</a>
</div></div>
<div class="popup popup_01"><div class="inner">
<h2 class="unforgettable"><strong>unforgettable</strong></h2>
<h2 class="brand">brand identities</h2>
</div></div>
<div class="popup popup_02"><div class="inner">
<h2 class="powerful">Powerful</h2>
<h2 class="elegant">& elegant</h2>
<p>development solutions that give<br>leverage to businesses of all sizes.</p>
</div></div>
</div><!-- /END #hannah_bg -->
</article><!-- /END #second -->
啊,打我吧。它在jsfiddle中的作用是因爲在.popup_next和 –
@ gilly3之間沒有額外的div(#hannah_bg)非常感謝!我完全看到了邏輯:'.parent()'不工作。我使用'.closest()'將其切換起來,它解決了空響應,但仍然沒有給我任何東西,這個小小的腳本正在殺死我。實際上,我在JSFiddle中測試了它,發現'.parent()'即使干擾HTML元素也能正常工作。 – Brian
嗚呼!得到它了!感謝一百萬,只是不得不與我不同的偏移量一起玩:) – Brian