如何在SQL Server 2008 R2中的一個查詢中運行distinct和Sum

Question

我有一個表＃1，如附圖所示。首先，我想總結所有不同ID的所有數量。然後要顯示具有相同數量的ID號。

Answer 1

試試這個創建臨時表

create table #Temp 
(
    id int, 
    qty int 
) 

Insert Into #Temp 
SELECT id, SUM(qty) 
     FROM yourTable 
     group by id 

SELECT * FROM #Temp 

SELECT Count(id) , qty 
     FROM #Temp 
     GROUP BY qty 
     ORDER BY qty DESC 

Answer 2

使用SUM和COUNT：

SELECT 
    COUNT(*) AS totalId, 
    qty 
FROM (
    SELECT 
     id, SUM(qty) AS qty 
    FROM tbl 
    GROUP BY id 
)t 
GROUP BY qty 

ONLINE DEMO

Answer 3

顯示所有不同ID的所有數量的總和：

SELECT id,SUM(qty) FROM table GROUP BY id; 

顯示ID的數量具有相同數量

SELECT count(id),quantity FROM (SELECT id,SUM(qty) AS quantity FROM table GROUP BY id) GROUP BY quantity