保存數據到表

Question

這是我的前一個問題的延伸： Auto generating dates based on a table

我得到了它完美的作品

with n as (
     select row_number() over (order by (select null)) - 1 as n 
     from master..spt_values 
    ) 
select t.*, dateadd(day, n.n, t.startDate) as thedate 
from t join 
    n 
    on dateadd(day, n.n, t.startDate) <= t.endDate; 

但是該決議，我想提出的通過將結果保存到表中來保持結果。可以持續數據嗎？我試過select into語句，但它沒有工作

整個語句是：收到

select into ABC 
(
    with n as (
      select row_number() over (order by (select null)) - 1 as n 
      from master..spt_values 
     ) 
    select t.*, dateadd(day, n.n, t.startDate) as thedate 
    from t join 
     n 
     on dateadd(day, n.n, t.startDate) <= t.endDate 
) 

錯誤是：

Msg 156, Level 15, State 1, Line 146 
Incorrect syntax near the keyword 'into'. 
Msg 319, Level 15, State 1, Line 148 
Incorrect syntax near the keyword 'with'. If this statement is a common table expression, an xmlnamespaces clause or a change tracking context clause, the previous statement must be terminated with a semicolon. 
Msg 102, Level 15, State 1, Line 168 
Incorrect syntax near ')'. 

如何將結果保存到一個表？

Answer 1

通知，其中into ABC是

;with n as (
    select row_number() over (order by (select null)) - 1 as n 
    from master..spt_values 
) 
select t.* 
    , dateadd(day, n.n, t.startDate) as thedate 
into ABC 
from t join n  
    on dateadd(day, n.n, t.startDate) <= t.endDate 

Answer 2

with n as (
      select row_number() over (order by (select null)) - 1 as n 
      from master..spt_values 
     ) 
with ABC as(
    select t.*, dateadd(day, n.n, t.startDate) as thedate 
    from t join 
     n 
     on dateadd(day, n.n, t.startDate) <= t.endDate 
) 

現在您可以在另一個查詢中使用Abc。