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我與此類似這裏的數據幀上的工作:排序列由特定序列R中
ID = c("1","1","1","1","1","1","1","2","2","2","2","2","2","2","2","2","2","2","2","2","2")
TIME = c("0", "0.5", "1","1.5","2","2.5","3","0","0", "0.5","0.5", "1","1","1.5","1.5","2","2","2.5","2.5","3","3")
OBS = c("0", "0.73", "0.98", "1.24", "2.06","2.56","4.01", "0", "0.03", "0.76", "0.85", "2.13","2.78","3.9", "4.1", "5.4", "5.6", "7.8", "8.0","8.4","8.8")
VISITNUM = c("1","1","1","1","1","1","1","1","2", "1","2","1","2","1","2","1","2","1","2","1","2")
DF = data.frame(ID, TIME, OBS, VISITNUM)
我有麻煩訂貨數據幀 - 基本上我想爲了通過我的數據下面的時間序列:
TIMEORDERED <- c("0","0.5","1","1.5","2","2","2.5","3")
給這個
ID = c("1","1","1","1","1","1","1","2","2","2","2","2","2","2","2","2","2","2","2","2","2")
TIME = c("0", "0.5", "1","1.5","2","2.5","3","0", "0.5", "1","1.5","2","2.5","3","0", "0.5", "1","1.5","2","2.5","3")
OBS= c("0", "0.73", "0.98", "1.24", "2.06","2.56","4.01", "0", "0.76", "2.13","3.9", "5.4", "7.8", "8.4", "0.03", "0.85", "2.78", "4.1","5.6","8.0","8.8")
VISITNUM = c("1","1","1","1","1","1","1","1","1","1","1","1","1","1","2","2","2","2","2","2","2")
DFIWANT = data.frame(ID, TIME, OBS, VISITNUM)
的問題是有關於測量相同的主題(DF $ ID = 2)(但不同的訪問,請參閱DF $ VISITNUM)。
我懷疑plyr包中的order()函數或arrange()函數是我的朋友,但我的努力並沒有取得豐碩的成果。
任何幫助,將不勝感激。
Sincerily Ÿ