SQL語句來生成列的值

Question

請參閱下面的DDL：

create table Person (ID int, [Type] int) 
insert into Person values (1,1) 
insert into Person values (2,1) 
insert into Person values (3,2) 
insert into Person values (4,3) 
insert into Person values (5,4) 
insert into Person values (6,5) 

我在尋找這樣一個結果：

2 1 1 1 1 

以下標準產生這樣的結果：

There are 2 persons with a type of 1 (The first column value is: 2) 
There is 1 person with a type of 2 (The second column value is: 1) 
There is 1 person with a type of 3 (The third column value is: 1) 
There is 1 person with a type of 4 (The forth column value is: 1) 
There is 1 person with a type of 5 (The fifth column value is: 1) 

Answer 1

使用CASE至SUM不同類型的

select sum(case when [Type] = 1 then 1 else 0 end), 
     sum(case when [Type] = 2 then 1 else 0 end), 
     sum(case when [Type] = 3 then 1 else 0 end), 
     sum(case when [Type] = 4 then 1 else 0 end), 
     sum(case when [Type] = 5 then 1 else 0 end) 
from tablename 

Answer 2

如果您希望info_message的通用性不如它的轉換爲只有1個計數，那麼我可以這樣做，但這需要我不認爲必要的案例邏輯。這取決於你。只要讓我知道你是否想讓我改變它。

DECLARE @Cnt_list VARCHAR(MAX) = 
            (
            SELECT CAST(COUNT(*) AS VARCHAR(10)) + ' ' 
            FROM Person 
            GROUP BY [Type] 
            ORDER BY [Type] 
            FOR XML PATH('') 
            ) 
SELECT @Cnt_list as cnt_list 

結果：

cnt_list 
---------- 
2 1 1 1 1 

然後，對於第二部分：

SELECT 'There are ' + CAST(COUNT(*) AS VARCHAR(10)) + ' person(s) with a type of ' + CAST([type] AS VARCHAR(10)) + '(The first column value is: ' + CAST(COUNT(*) AS VARCHAR(10)) + ')' info_message 
FROM Person 
GROUP BY [Type] 

結果：

info_message 
-------------------------------------------------------------------- 
There are 2 person(s) with a type of 1(The first column value is: 2) 
There are 1 person(s) with a type of 2(The first column value is: 1) 
There are 1 person(s) with a type of 3(The first column value is: 1) 
There are 1 person(s) with a type of 4(The first column value is: 1) 
There are 1 person(s) with a type of 5(The first column value is: 1)