3
所以我有一個看起來像JSON對象的數組:從一個條件的json對象追加字符串一起高效?
data = [{key1: 123, key2:"this is the first string to concatenate"},
{key1: 131, key2:"this is the second string to concatenate"},
{key1: 152, key2:"this is the third string to concatenate"} ]
基本上,我使用的是for循環,現在如下:
all_key2 = ""
data = json.load(json_file)
for p in data:
#make it all one big string
if langid.classify(p["key2"])=="english":
all_key2 = p["key2"] + " " + all_key2
所以答案應該是:
"this is the first string to concatenate this is the second string to concatenate this is the third string to concatenate"
但是這花了很多時間,因爲我有一個bajillion對象和長字符串。有沒有更快的方法來完成這種聯合編排?
[編輯]正在調查lambda功能,可能是要走的路?
upvote for list-,而不是gencomp with join。 – timgeb
是否應該顛倒(數據)?該OP正在加入 –
@Luchko謝謝! Concat順序對我無關緊要,我會考慮加入:) – ocean800