如何計算使用PIVOT表，沒有UNION，ROLLUP或CUBE的總行？

Question

有人可以幫忙計算這個PIVOT表底部的總行嗎？

select *, [Drug1] + [Drug2] + [Drug3] + [Drug4] + [Drug5] as [Total] 
from 
     (Select [id], [drug], [Diagnosis] 
      from DrugDiagnosis 
     ) as ptp 
     pivot 
      (count(id) 
       for drug 
       in ([Drug1], [Drug2], [Drug3], [Drug4], [Drug5]) 
      ) as PivotTable 

我知道我可以用UNION做，並有一個單獨的查詢來計算總數，但這會使數據庫的命中率翻倍。

我找到了使用ROLLUP和CUBE的例子，但是這些都是不推薦使用的功能，所以我不想使用它們。

任何其他想法，GROUPING SETS也許？

Answer 1

您可以使用GROUPING SETS獲得總計行：

select isnull(diagnosis, 'Total') Diagnosis, 
    sum([Drug1]) Drug1, sum([Drug2]) Drug2, 
    sum([Drug3]) Drug3, sum([Drug4]) Drug4, 
    sum([Drug5]) Drug5, 
    sum([Drug1] + [Drug2] + [Drug3] + [Drug4] + [Drug5]) as [Total] 
from 
(
    Select [id], [drug], [Diagnosis] 
    from DrugDiagnosis 
) as ptp 
pivot 
(
    count(id) 
    for drug in ([Drug1], [Drug2], [Drug3], [Drug4], [Drug5]) 
) as PivotTable 
group by grouping sets((diagnosis),()); 

見SQL Fiddle with Demo