我應該如何將我的json代碼包含在我的php文件和html文件中

這些是我的代碼。我的PHP頁面：我應該如何將我的json代碼包含在我的php文件和html文件中

$con = mysqli_connect($host, $username, $password, $db_name); 
if (!$con) { 
    die('Could not connect: ' . mysqli_error($con)); 
} 

mysqli_select_db($con,"ajax_demo"); 

$sql = "SELECT problem.id, problem.DateTimeCreated, status.status_desc, users.username FROM problem 
       JOIN issue ON problem.issue_id = issue.id 
       JOIN status ON problem.status = status.id 
       JOIN users ON problem.reported_account_id = users.id 
       where issue_id = '3'"; 

$result = mysqli_query($con,$sql); 

echo '<table width="200" border="0" cellpadding="0" cellspacing="0">'; 
echo "<table> 
     <tr> 
     <th>Unique ID</th> 
     <th>Date</th> 
     <th>Status</th> 
     <th>Reported by</th> 
     </tr>"; 

while($row = mysqli_fetch_array($result)) { 
    echo "<tr>"; 
    echo "<td>" . $row['id'] . "</td>"; 
    echo "<td>" . $row['DateTimeCreated'] . "</td>"; 
    echo "<td>" . $row['status_desc'] . "</td>"; 
    echo "<td>" . $row['username'] . "</td>"; 

    echo "</tr>"; 
} 
echo "</table>"; 

mysqli_close($con);

我的html代碼：

<script> 
function display(){ 
    var xmlhttp = new XMLHttpRequest(); 
    var url = serverURL() + "/gwifiv2.php"; 

    xmlhttp.onreadystatechange=function() { 
     if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { 
     } 
    } 
    xmlhttp.open("GET", url, true); 
    xmlhttp.send(); 
} 
</script> 
</head> 

<body> 
<div data-role="page" data-theme="a"> 
    <div data-role="header" data-position="inline"> 
     <a href="index.html" data-icon="home" data-theme="a"><br></a> 
     <h1>Issues</h1> 
     <a href="domain.html" data-icon="arrow-l" data-theme="a"><br></a> 
    </div> 
    <div data-role="content" data-theme="a"> 
     <div data-role="main" class="ui-content"> 
      <table data-role="table" data-mode="columntoggle" class="ui-responsive ui-shadow" id="myTable"> 
       <thead> 
        <form> 
         <input type="button" value="Display" onclick="display()"> 
        </form> 
        <tr> 
         <th>Unique ID</th> 
         <th data-priority="1">Date</th> 
         <th data-priority="2">Status</th> 
         <th data-priority="3">Ticket</th> 
        </tr> 
       </thead>

我無法顯示從數據庫上我的HTML代碼得到我的PHP表。如果我直接輸入我的php頁面的url，它會顯示錶格，但是當我將我的代碼插入到我的andriod設備時，表格不顯示。

來源

2015-12-03 Sihui

您必須定義div或在點擊時顯示服務器響應的地方。我稍微修改了JavaScript和HTML以正確呈現AJAX響應。

這裏是改性html

<script> 
function display(){ 
    var xmlhttp = new XMLHttpRequest(); 
    var url = serverURL() + "/gwifiv2.php"; 

    xmlhttp.onreadystatechange=function() { 
     if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { 
      document.getElementById("test").innerHTML=xmlhttp.responseText; 
     } 
    } 
    xmlhttp.open("GET", url, true); 
    xmlhttp.send(); 
} 
</script> 
</head> 

<body> 
<div data-role="page" data-theme="a"> 
    <div data-role="header" data-position="inline"> 
     <a href="index.html" data-icon="home" data-theme="a"><br></a> 
     <h1>Issues</h1> 
     <a href="domain.html" data-icon="arrow-l" data-theme="a"><br></a> 
    </div> 
    <div data-role="content" data-theme="a"> 
     <div data-role="main" class="ui-content"> 
      <table data-role="table" data-mode="columntoggle" class="ui-responsive ui-shadow" id="myTable"> 
       <thead> 
        <form> 
         <input type="button" value="Display" onclick="display()"> 
         <div id="test"></div> 
        </form> 
        <tr> 
         <th>Unique ID</th> 
         <th data-priority="1">Date</th> 
         <th data-priority="2">Status</th> 
         <th data-priority="3">Ticket</th> 
        </tr> 
       </thead>

來源

2015-12-03 07:42:02

我應該如何將我的json代碼包含在我的php文件和html文件中

回答

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