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我創建了一個例子來理解併發HashMap,但它似乎在7-8次運行後給出了不確定的輸出。ConcurrentHashMap在多線程應用中沒有給出正確的輸出
在我的例子中,我創建了三個線程(它們模仿三個服務來獲取數學,科學,英語的分數),它更新了一個只有3個鍵值對的共享HashMap(鍵是三個名字A,B,C並在運行結束時的值應該是三個科目的累積分數)
我發佈了下面的代碼,請注意。
錯誤的輸出如下所示(正確的應該結束等來全部完成主:{C = 27,A = 57,B = 42})
Within run Math : {C=0, A=0, B=0}
Within run Science : {C=0, A=0, B=0}
Completed Science : {C=10, A=39, B=29}
Completed Math : {C=10, A=39, B=29}
Within run English : {C=0, A=0, B=0}
Completed English : {C=18, A=57, B=42}
All Done main : {C=18, A=57, B=42}
ConcurrentHashMapExample類:
package com.ll.thread.concurrency;
import java.util.Iterator;
import java.util.concurrent.ConcurrentHashMap;
import java.util.concurrent.CountDownLatch;
public class ConcurrentHashMapExample {
public static void main(String[] args) {
// TODO Auto-generated method stub
ConcurrentHashMap<String, Integer> concurrentHashMap = new ConcurrentHashMap<String, Integer>();
concurrentHashMap.put("A", 0);
concurrentHashMap.put("B", 0);
concurrentHashMap.put("C", 0);
CountDownLatch countDownLatch = new CountDownLatch(3);
Runnable runnableScience = new Worker(concurrentHashMap , "Science" , countDownLatch);
Runnable runnableMath = new Worker(concurrentHashMap , "Math" , countDownLatch);
Runnable runnableEnglish = new Worker(concurrentHashMap , "English" , countDownLatch);
new Thread(runnableScience , "Science").start();
new Thread(runnableMath ,"Math").start();
new Thread(runnableEnglish ,"English").start();
try {
countDownLatch.await();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("All Done " + Thread.currentThread().getName() + " : "+concurrentHashMap);
concurrentHashMap = null;
}
}
Worker類:
package com.ll.thread.concurrency;
import java.util.Iterator;
import java.util.concurrent.ConcurrentHashMap;
import java.util.concurrent.CountDownLatch;
public class Worker implements Runnable{
ConcurrentHashMap<String, Integer> concurrentHashMap ;
String threadName = "";
CountDownLatch countDownLatch ;
public Worker(ConcurrentHashMap<String, Integer> concurrentHashMap,
String subject, CountDownLatch countDownLatch) {
this.concurrentHashMap = concurrentHashMap;
this.threadName = subject ;
this.countDownLatch = countDownLatch;
// TODO Auto-generated constructor stub
}
@Override
public void run() {
// TODO Auto-generated method stub
System.out.println("Within run " +Thread.currentThread().getName() + " : "+concurrentHashMap);
try{
for(Iterator<String> iterator = concurrentHashMap.keySet().iterator() ; iterator.hasNext();){
String key = iterator.next();
//synchronized (this) {
if("Math".equals(Thread.currentThread().getName())) {
if("A".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) +20);
else if("B".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) + 15);
else if("C".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) +10);
}else
if("Science".equals(Thread.currentThread().getName())) {
if("A".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) +19);
else if("B".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) +14);
else if("C".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) +9);
}
else
if("English".equals(Thread.currentThread().getName())) {
if("A".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) +18);
else if("B".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) +13);
else if("C".equals(key))
concurrentHashMap.put(key, concurrentHashMap.get(key) +8);
}
}
// }
}
finally{
System.out.println("Completed " + Thread.currentThread().getName() + " : " + concurrentHashMap);
countDownLatch.countDown();
}
}
}
什麼辦法? 'Concurrent'(在'ConcurrentHashMap'中)意味着,爲了保護其內部結構,映射儘可能地保持同步。這並不意味着,使用它會自動修復使用地圖的代碼中的競爭條件。 – Dirk
'concurrentHashMap.put(key,concurrentHashMap.get(key)+19);'不是原子的:地圖可以在get和put之間更新... – assylias
你沒有正確使用它顯示的代碼!我建議你從閱讀接口ConcurrentMap(ConcurrentHashMap是一個實現)的javadocs開始,特別是理解爲什麼需要新方法 – Scorpion