添加COUNT（和限定），以SQL語句

Question

我的數據庫中有3行（未列出的所有列）：

**uFirst** | **uApp** 
    Dave  | approved 
    John  | declined 
    Jane  | no 

這個SQL工作，並顯示所有行：

SELECT u.uID, u.uManT, u.uFirst AS 'NomFN', m.uFirst AS 'ManFN', u.uLast AS 'NomLN', m.uLast AS 'ManLN', u.uNomd, u.uApp, u.uApp, u.uAppd, u.uRep, u.uRepd, u.uManT, u.uStatus, u.uManR 
      FROM users AS u LEFT OUTER JOIN users AS m 
      ON u.uManT = m.uID 
      WHERE u.uManR = " . $luID . " 
      AND u.uStatus = 'Physician' 
      ORDER BY u.uLast ASC"; 

當我嘗試添加COUNT，只顯示1行（經批准的）：

SELECT COUNT(CASE WHEN u.uApp = 'approved' THEN 1 END) AS Approved, 
     COUNT(CASE WHEN u.uApp = 'declined' THEN 1 END) AS Declined, 
     u.uID, u.uManT, u.uFirst AS 'NomFN', m.uFirst AS 'ManFN', u.uLast AS 'NomLN', m.uLast AS 'ManLN', u.uNomd, u.uApp, u.uApp, u.uAppd, u.uRep, u.uRepd, u.uManT, u.uStatus, u.uManR 
      FROM users AS u LEFT OUTER JOIN users AS m 
      ON u.uManT = m.uID 
      WHERE u.uManR = " . $luID . " 
      AND u.uStatus = 'Physician' 
      ORDER BY u.uLast ASC"; 

我想顯示所有的行，數的計數的用戶被批准。我究竟做錯了什麼？

Answer 1

在這種情況下，因爲你不使用GROUP BY剛剛返回1行，此查詢應該得到你想要的東西：

SELECT COUNT(uFirst) AS Total, u.uID, u.uManT, 
    u.uFirst AS 'NomFN', m.uFirst AS 'ManFN', u.uLast AS 'NomLN', 
    m.uLast AS 'ManLN', u.uNomd, u.uApp, u.uApp, u.uAppd, u.uRep, 
    u.uRepd, u.uManT, u.uStatus, u.uManR 
FROM users AS u 
LEFT OUTER JOIN users AS m ON u.uManT = m.uID 
WHERE u.uManR = " . $luID . " AND u.uStatus = 'Physician' 
GROUP BY uApp 
ORDER BY u.uLast ASC";