定義上述模式,併爲每個屬性指定適當的類型。
Employees
{
Employee_id, int, PK
Name, nvarchar(50)
}
Childs
{
Child_id, int, PK
Employee_id, int, FK
Name, nvarchar(50)
Birthday, date
}
Skills
{
Skill_id, int, PK
Employee_id, int, FK
Type, nvarchar(50)
}
Exams
{
Exam_id, int, PK
Skill_id, int, FK
Year, int
City, nvarchar(50)
}
找到誰擁有一個孩子出生在1月1日或以後所有員工的名字,2000
MyDBEntities db = new MyDBEntities();
var result = from e in db.Employees
join c in db.Childs
on e.Employee_id equals c.Employee_id
where e.Birthday >= new DateTime(2000, 1, 1)
select e;
查找誰參加升學考試的技能型「打字」的員工在城市的 「頓」
var result = from e in db.Employees
join s in db.Skills
on e.Employee_id equals s.Employee_id
join x in db.Exams
on s.Skill_id equals x.Skill_id
where s.Type.Equals("typing") && x.City.Equals("Dayton")
select e;
中列出的關係,員工的所有技能類型
var result = from e in db.Employees
join s in db.Skills
on e.Employee_id equals s.Employee_id
select new EmployeeSkill()
{
EmployeeName = e.Name,
SkillType = s.Type
};
底線...... LINQ2SQL規則:)
現在......你只需要轉換的LINQ to SQL和你有你的功課做;)
(你不希望讓所有在這裏完成,右)
什麼是「多集」是指在這方面? – 2010-11-07 09:22:04
@Daniel:[「家庭作業標籤與其他所謂的'meta'標籤一樣,現在不鼓勵。」](http://meta.stackexchange.com/q/10812) – 2010-11-07 23:37:37