SQL Server XML替換屬性中的值

Question

我想要替換XML中屬性的值。該屬性在xml中多次出現。我怎麼能代替這些一次性

我的XML lools一些什麼樣的如下：

<Example> 
    <A> 
    <B Type = "x">qqq</B> 
    <B Type = "x">www</B> 
    </A> 
    <C> 
    <D Type = "x">aaa</D> 
    <D Type = "x">uuu</D> 
    </C> 
</Example> 

我想Ÿ

Answer 1

全部更換x你不能代替一次性使用replace value of (XML DML)。你必須循環做。

declare @xml xml = ' 
<Example> 
    <A> 
    <B Type = "x">qqq</B> 
    <B Type = "x">www</B> 
    </A> 
    <C> 
    <D Type = "x">aaa</D> 
    <D Type = "x">uuu</D> 
    </C> 
</Example> 
' 

while (select @xml.exist('//*[@Type = "x"]')) = 1 
begin 
    set @xml.modify('replace value of (//*[@Type = "x"]/@Type)[1] with "y"') 
end 

select @xml 

結果：

<Example> 
    <A> 
    <B Type="y">qqq</B> 
    <B Type="y">www</B> 
    </A> 
    <C> 
    <D Type="y">aaa</D> 
    <D Type="y">uuu</D> 
    </C> 
</Example> 

更新

替換值X和Z與Y：

while (select @xml.exist('//*[@Type = ("x","z")]')) = 1 
begin 
    set @xml.modify('replace value of (//*[@Type = ("x","z")]/@Type)[1] with "y"') 
end 

，其中y替換所有值：

while (select @xml.exist('//*[@Type != "y"]')) = 1 
begin 
    set @xml.modify('replace value of (//*[@Type != "y"]/@Type)[1] with "y"') 
end