MySQL的：之間的多個時間範圍

表結構和樣本數據MySQL的：之間的多個時間範圍

CREATE TABLE IF NOT EXISTS `orders` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `customer_id` int(11) NOT NULL, 
    `restaurant_id` int(11) NOT NULL, 
    `bill_id` int(11) NOT NULL, 
    `source_id` int(1) NOT NULL, 
    `order_medium_id` int(11) NOT NULL, 
    `purchase_method` varchar(255) NOT NULL, 
    `totalamount` int(11) NOT NULL, 
    `delivery_charg` int(11) NOT NULL, 
    `discount` int(11) NOT NULL, 
    `vat` int(11) NOT NULL, 
    `total_price` int(11) NOT NULL DEFAULT '0', 
    `date_created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, 
    PRIMARY KEY (`id`), 
    KEY `customer_id` (`customer_id`), 
    KEY `source_id` (`source_id`), 
    KEY `restaurant_id` (`restaurant_id`), 
    KEY `bill_id` (`bill_id`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=22 ; 

-- 
-- Dumping data for table `orders` 
-- 

INSERT INTO `orders` (`id`, `customer_id`, `restaurant_id`, `bill_id`, `source_id`, `order_medium_id`, `purchase_method`, `totalamount`, `delivery_charg`, `discount`, `vat`, `total_price`, `date_created`) VALUES 
(1, 1, 1, 1, 1, 0, 'cash', 1600, 0, 0, 0, 1600, '2016-05-29 13:05:40'), 
(2, 1, 1, 2, 2, 1, 'cash', 1820, 0, 0, 0, 1820, '2016-06-27 07:21:25'), 
(4, 1, 1, 3, 3, 0, 'cash', 1770, 0, 0, 0, 1770, '2016-05-31 13:05:56'), 
(5, 1, 1, 4, 2, 1, 'cash', 1300, 0, 0, 0, 1300, '2016-06-27 07:21:31'), 
(6, 1, 1, 5, 1, 0, 'cash', 950, 0, 0, 0, 950, '2016-06-02 13:06:15'), 
(7, 1, 1, 6, 1, 0, 'cash', 1640, 0, 0, 0, 1640, '2016-06-03 13:06:24'), 
(8, 1, 1, 7, 2, 2, 'cash', 1600, 0, 0, 0, 1600, '2016-06-27 07:21:36'), 
(9, 1, 1, 8, 2, 2, 'cash', 1575, 0, 0, 0, 1575, '2016-06-27 07:21:40'), 
(10, 1, 1, 9, 3, 0, 'cash', 1125, 0, 0, 0, 1125, '2016-06-06 13:06:48'), 
(11, 1, 1, 10, 2, 3, 'cash', 1920, 0, 0, 0, 1920, '2016-06-27 07:21:51');

獲取分段記錄要求：

I want to segment records as per customer as following. 
1. customers who ordered in last 2 week then give ratingflag 5 
2. customers who ordered between 2 weeks to 4 week then give ratingflag 3 
3. customers who ordered between 4 weeks to 8 week then give ratingflag 2 
and so on.

客戶應是唯一的。我們根據需要撰寫查詢記錄。我的表中沒有太多數據，所以我根據自己的數據進行了條件變更。

我試過了。我將不勝感激，如果你能幫助我做同樣的更好的方法：

查詢我試圖

select customer_id,rating from (select `customer_id`,5 as rating from orders where `restaurant_id` = 1 and (DATE(`date_created`) between DATE(DATE_SUB(NOW(), INTERVAL 1 DAY)) AND DATE(NOW())) GROUP BY customer_id 
UNION ALL 
select `customer_id`,4 as rating from orders where `restaurant_id` = 1 and (DATE(`date_created`) BETWEEN DATE(DATE_SUB(NOW(), INTERVAL 4 DAY)) AND DATE(DATE_SUB(NOW(), INTERVAL 2 DAY))) GROUP BY customer_id 
UNION ALL 
select `customer_id`,3 as rating from orders where `restaurant_id` = 1 and (DATE(`date_created`) BETWEEN DATE(DATE_SUB(NOW(), INTERVAL 8 DAY)) AND DATE(DATE_SUB(NOW(), INTERVAL 5 DAY))) GROUP BY customer_id 
UNION ALL 
select `customer_id`,2 as rating from orders where `restaurant_id` = 1 and (DATE(`date_created`) BETWEEN DATE(DATE_SUB(NOW(), INTERVAL 20 DAY)) AND DATE(DATE_SUB(NOW(), INTERVAL 9 DAY))) GROUP BY customer_id 
UNION ALL 
select `customer_id`,1 as rating from orders where `restaurant_id` = 1 and (DATE(`date_created`) BETWEEN DATE(DATE_SUB(NOW(), INTERVAL 40 DAY)) AND DATE(DATE_SUB(NOW(), INTERVAL 21 DAY))) GROUP BY customer_id) as temp group by customer_id order by rating desc;

來源

2016-07-05 Navjot Singh

嗯，我覺得你只是想在最近的訂單的日期和大案聲明。例如：

select o.customer_id, 
     (case when max(date_created) >= date_sub(now(), interval 2 week) then 1 
      when max(date_created) >= date_sub(now(), interval 4 week) then 2 
      when max(date_created) >= date_sub(now(), interval 8 week) then 3 
      . . . 
     end) as rating 
from orders o 
group by o.customer_id;

請注意，case按順序評估條件。這就是爲什麼between沒有必要。第一個匹配條件結束了case的處理。

來源

2016-07-05 12:20:50

MySQL的：之間的多個時間範圍

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