2016-07-06 102 views
-1

我試圖實現一個自定義的上下文菜單,該菜單項將出現在節點周圍,思路如下,在目標節點周圍繪製一個虛擬圓,並計算圓的周長,第一個菜單項將在目標節點的頂部,其餘的將在每個菜單項之間以相等的距離分配,,,,我沒有寫任何代碼行,因爲我不知道如何啓動至少,,, PLZ的幫助?JavaFX顯示節點周圍的選項

也許這個形象將更好地解釋

enter image description here

+1

[谷歌JavaFX的徑向菜單] (https://www.google.com/?q=javafx+radial+menu&gws_rd=ssl#) – jewelsea

+0

所以你有[極座標,想轉換爲笛卡爾座標?](https://en.wikipedia。 org/wiki/Polar_coordinate_system#Converting_between_polar_and_Cartesian_coordinates) – fabian

+0

@fabian我想我現在就可以開始編碼,,, http://www.ajdesigner.com/phpcircle/circle_arc_length_theta.php –

回答

0

萬一有人有興趣,我manged做到這一點,但代碼是有點兒髒:

import javafx.scene.control.Button; 
import javafx.scene.layout.StackPane; 
import javafx.scene.shape.Circle; 
import lombok.AccessLevel; 
import lombok.NoArgsConstructor; 

/** 
    * @author Asendar 
* 
*/ 
@NoArgsConstructor(access = AccessLevel.PRIVATE) 
public final class RadialMenuFactory { 
    public static final RadialMenuFactory instance = new RadialMenuFactory(); 

    public StackPane construct(int itemsCount, int radius) { 
     StackPane pane = new StackPane(); 

     double pheta = 270; 

     int counter = 0; 

     while (counter != itemsCount) { 
      double x = radius * Math.cos(Math.toRadians(pheta)); 
      double y = radius * Math.sin(Math.toRadians(pheta)); 

      Button btn = new Button("btn"); 

      btn.setTranslateX(x); 
      btn.setTranslateY(y); 

      pane.getChildren().addAll(btn); 

      pheta += 360/itemsCount; 
      pheta %= 360; 

      counter++; 
     } 

     pane.setMinHeight(300); 
     pane.setMinWidth(300); 

     return pane; 
    } 

}