總結多列 - 意外的結果

Question

爲什麼

這是不是給出不正確的結果？

SELECT 
    people.name, 
    SUM(allorders.TOTAL), 
    SUM(allorders.DISCOUNT), 
    SUM(allorders.SERVICECHARGE), 
    SUM(payments.AMOUNT) 
FROM 
    people 
INNER JOIN 
    allorders ON allorders.CUSTOMER = people.ID 
INNER JOIN 
    payments ON payments.CUSTOMER = people.ID 
WHERE 
    people.ID = 7 AND allorders.VOIDED = 0 AND payments.VOIDED = 0 

得到：（名），1644000，1100000，50000，1485000

如果我做兩個表在時間（INNER JOIN人allorders.CUSTOMER = people.ID）在單獨的查詢，我得到了正確的結果。我甚至不知道我得到的數字來自哪裏。像：

SELECT 
    people.name, 
    SUM(allorders.TOTAL), 
    SUM(allorders.DISCOUNT), 
    SUM(allorders.SERVICECHARGE) 
FROM 
    people 
INNER JOIN 
    allorders ON allorders.CUSTOMER = people.ID 
WHERE people.ID = 7 AND allorders.VOIDED = 0 

得到：（名），822000，550000 25000

SELECT 
    people.name, 
    SUM(payments.AMOUNT) 
FROM 
    people 
INNER JOIN payments ON payments.CUSTOMER = people.ID 
WHERE people.ID = 7 AND payments.VOIDED = 0 

得到：（名），297000

它看起來就像雙打，但我不」不知道爲什麼。

奇怪的是我有一個類似的查詢，正確地做到了這一點。我會發布它，但它有點複雜。這裏是：

SELECT 
    t1.IDENTIFIER, 
    ifnull(t1.NAME,""), 
    t1.PRICE, 
    t1.GUESTS, 
    t1.STATUS, 
    ifnull(t1.NOTE,""), 
    t1.LINK, 
    ifnull(t1.EDITOR,""), 
    concat(t2.FIRSTNAME,"",t2.LASTNAME), 
    t2.ID, 
    t3.ID, 
    ifnull(t1.EMAIL,""), 
    ifnull(t3.PHONE,""), 
    ifnull(SUM(p1.AMOUNT),0), 
    ifnull(SUM(o1.DISCOUNT),0), 
    ifnull(SUM(o1.TOTAL),0), 
    ifnull(SUM(o1.SERVICECHARGE),0) 
FROM 
    tables t1 
INNER JOIN 
    people t2 ON t1.SELLER = t2.ID 
INNER JOIN 
    people t3 ON t1.CUSTOMER = t3.ID 
INNER JOIN 
    orderpaymentinfo ON orderpaymentinfo.TABLEID = t1.IDENTIFIER 
INNER JOIN 
    payments p1 ON orderpaymentinfo.PAYMENTID = p1.PAYMENTID 
INNER JOIN 
    allorders o1 ON o1.ORDERID = orderpaymentinfo.ORDERID 
WHERE 
    p1.VOIDED = 0 AND o1.VOIDED = 0 AND t1.DATE = "2014-12-20" 
GROUP BY t1.IDENTIFIER 

後者聲明做同樣的連接，只是它使用一個額外的輔助表。我很抱歉它格式有點不好（我對SO的格式化程序不太瞭解），但是如果有人能告訴我這兩個語句中的邏輯與另一個語句中的完全錯誤之間的區別，我會非常高興。

響應回答：

結果1：

Name - 5 

結果2：

Name - 2 

結果3：

Name - 10 

結果4是在phpMyAdmin截斷 - 我會在哪裏得到這很容易？

三個表格的表格結構如下所示：

SHOW正在創建中。

Answer 1

好了，所以我敢肯定你已經連接條件這基本上爆炸的結果集變得像一個笛卡爾乘積。這就是我想你應該嘗試

首先，運行以下和共享輸出：

SELECT p.name,COUNT(*) 
FROM people as p 
INNER JOIN allorders AS a 
ON a.CUSTOMER = p.ID 
WHERE p.ID = 7 AND a.VOIDED = 0 
GROUP BY p.name 

然後運行

SELECT p.name,COUNT(*) 
FROM people AS p 
INNER JOIN payments AS pay 
ON pay.CUSTOMER = p.ID 
WHERE p.ID = 7 AND pay.VOIDED = 0 
GROUP BY p.name 

然後運行

SELECT 
     p.name, 
     COUNT(*) 
    FROM 
     people as p 
    INNER JOIN 
     allorders as a ON a.CUSTOMER = p.ID 
    INNER JOIN 
     payments as pay ON pay.CUSTOMER = p.ID 
    WHERE 
     p.ID = 7 AND a.VOIDED = 0 AND pay.VOIDED = 0 
    GROUP BY p.name 

末運行以下

SHOW CREATE TABLE people; 
SHOW CREATE TABLE payments; 
SHOW CREATE TABLE allorders; 

問題是您沒有正確理解您的數據。你需要給我們更多關於數據和關係的信息，我在這裏描述的輸出應該會有所幫助。我不是一個答案。但是，如果您運行這些查詢並粘貼它們的輸出，則應該能夠從我或其他人那裏獲得答案。基於上述討論

及以上的編輯，請嘗試：

SELECT 
    p.name, 
    SUM(o.TOTAL), 
    SUM(o.DISCOUNT), 
    SUM(o.SERVICECHARGE), 
    MAX(pay.amt) 
FROM 
    people as p 
INNER JOIN 
    allorders AS o ON o.CUSTOMER = p.ID 
INNER JOIN (SELECT customer, 
      SUM(amount) as amt 
      FROM payments 
      WHERE voided = 0 AND customer = 7 
      GROUP BY customer) AS pay 
    ON pay.customer = p.id 
WHERE 
    p.ID = 7 AND o.VOIDED = 0 
GROUP BY p.name 

你也可以在你的SELECT語句做一個子查詢，但它很討厭海事組織。你也可以做min（pay.amt）或者avg，甚至可以把總計放在一起。以上應該工作...即使有更乾淨的方式。我提供了這個答案，所以你可以推斷你爲什麼會得到意想不到的結果......實際上，優化你的查詢是一個不同的問題，你可以稍後進入，一旦你有機會看看這個