3
SELECT DISTINCT MonthName(Month([Date])) AS [Month], tblSupportCalls.System, Count(tblSupportCalls.System) AS [Total for System], Year([Date]) AS [Year]
FROM tblSupportCalls
WHERE (((tblSupportCalls.Date) Between Now() And Now()-7) AND ((tblSupportCalls.System) In ('Career Campus','E-PEEP')) AND ((tblSupportCalls.StartTime) Is Not Null) AND ((Hour([StartTime]))>=7))
GROUP BY tblSupportCalls.System, tblSupportCalls.Date;
每當我輸入的是它給了我多個月,如:快速SQL問題日期
July
July
July
我希望它只是說七月僅有1點時,我無法弄清楚,爲什麼永遠場重複不同的日子。我只想說:
MONTH |系統|總系統|我所期待的一年
是
> MONTH | System | Total Systems | Year
> July CC 2 2010
> July CC 7 2010
> July CC 9 2010
> July EE 1 2010
> July EE 2 2010
需要是:
MONTH | System | Total Systems | Year
July CC 18 2010
July EE 03 2010
展示了你可以張貼一個你在談論喬的例子。我已經嘗試過,但我可能輸入了錯誤 – Alex 2011-03-01 21:54:16
@Alex:我已將group by子句添加到我的答案中。 – 2011-03-01 21:57:08
需要按3個字段分組。另外,groupname中不需要monthname,它可以在select中針對分組'month(date)' – RichardTheKiwi 2011-03-01 21:57:44