SQL選擇行不是另一

Question

我有SQL其中將包含一個ID的多個行的表，如下

accountid Productname 
1   GL 
1   IP 
1   MI 
2   GL 
2   IP 
2   PA 
3   MI 
3   CP 
3   IP 
4   GL 
4   CP 
4   CI 

我希望能夠選擇具有一定的產品的所有帳戶但不是其他。例如對於所有具有IP或GL而不是MI，使用上面這個示例表將返回賬戶2和4

SELECT ccx_accountidname 
FROM (
    SELECT ccx_accountidname, ccx_productname 
    FROM Filteredccx_leadresearch 
    WHERE ccx_productname IN ('GL','IP') 
    AND ccx_accountidname IS NOT NULL 
    ) AS T 
WHERE ccx_productname NOT IN ('MI') 
ORDER BY ccx_accountidname 

和

SELECT DISTINCT LR1.ccx_accountidname 
FROM Filteredccx_leadresearch LR1 
LEFT JOIN Filteredccx_leadresearch LR2 ON LR1.ccx_accountid = LR2.ccx_accountid 
AND LR2.ccx_productname IN ('GL', 'IP') 
WHERE LR1.ccx_productname NOT IN ('MI') 
AND LR1.ccx_accountidname IS NOT NULL 
ORDER BY LR1.ccx_accountidname 

均可以得到基本相同的結果，沒有任何這可以做到嗎？

預先感謝任何幫助

Answer 1

你能試試這個：

SELECT DISTINCT T1.Accountidname FROM TheTableThatContainsAccountnames as T1 
JOIN AccountProductsTable as T2 on T1.AccountId=T2.AccountId 
WHERE T2.ProductName = 'ProductYouWant' 
AND T2.ProductName = 'AnOtherProductYouWant' 

Answer 2

根據您的文章，你真正需要的是正確的和邏輯的簡單查詢。您需要產品名稱爲GL或IP但不在MI中的所有帳戶。這將做到沒有任何其他聯接。

SELECT ccx_accountidname 
    FROM Filteredccx_leadresearch 
    WHERE 
     ccx_productname in ('GL','IP') 
     and ccx_productname not in ('MI') 

編輯

這將讓你的帳戶，但我懷疑它會在你的整體解決方案。沒有看到完整的數據集就很難說清楚。這也可以通過參數完成。

IF OBJECT_ID('tempdb..#TempTable') IS NOT NULL 
DROP TABLE #TempTable 

IF OBJECT_ID('tempdb..#TempTableTwo') IS NOT NULL 
DROP TABLE #TempTableTwo 

create table #TempTable (accountid int, productname char(2)) 
insert into #TempTable (accountid,productname) values 
(1,'GL'), 
(1,'IP'), 
(1,'MI'), 
(2,'GL'), 
(2,'IP'), 
(2,'MA') 


select distinct 
    t1.accountid, 
    1 as T 
into #TempTableTwo 
from 
    #TempTable t1 
where 
    productname in ('GL','IP') 
union all 
select distinct 
    t1.accountid, 
    -1 as T 
from 
    #TempTable t1 
where 
    productname in ('MI') 

select 
    accountid 
from #TempTableTwo 
group by accountid 
having sum(T) > 0