2011-01-14 28 views

回答

15

大多數數據庫都支持這一點:

SELECT 
    table_name 
FROM 
    information_schema.columns 
WHERE 
    column_name = 'x' 
+2

去(只要SO都會讓我將其標記)標記這個作爲答案,因爲它返回一個額外的表另一個答案沒有...... – Scott 2011-01-14 01:07:50

1

試試這個

SELECT t.name as TableName, c.name as ColumnName 
FROM sys.tables t 
JOIN sys.columns c ON t.object_id = c.object_id 
WHERE c.name = 'RCPTNMBR' 
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