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我想彈出一個窗口與想要將文件上傳到服務器的人進行交互。我要呈現在新窗口中的文件輸入形式,但我不能讓它做運行如下:我可以渲染一個Ext.FormPanel到一個新的Ext.window嗎?
var win = new Ext.Window();
var fp = new Ext.FormPanel({
renderTo: win,//I just guess that I can render this to the window I created...
fileUpload: true,
width: 500,
frame: true,
title: 'File Upload Form',
autoHeight: true,
bodyStyle: 'padding: 10px 10px 0 10px;',
labelWidth: 50,
defaults: {
anchor: '95%',
allowBlank: false,
msgTarget: 'side'
},
items: [{
xtype: 'textfield',
fieldLabel: 'Name'
},{
xtype: 'fileuploadfield',
id: 'form-file',
emptyText: 'Select an image',
fieldLabel: 'Photo',
name: 'photo-path',
buttonText: '',
buttonCfg: {
iconCls: 'upload-icon'
}
}],
buttons: [{
text: 'Save',
handler: function(){
if(fp.getForm().isValid()){
fp.getForm().submit({
url: 'file-upload.php',
waitMsg: 'Uploading your photo...',
success: function(fp, o){
msg('Success', 'Processed file "'+o.result.file+'" on the server');
}
});
}
}
},{
text: 'Reset',
handler: function(){
fp.getForm().reset();
}
}]
});
win.show();