2
嘿大家都希望一切順利。我有這樣的代碼，一個MySQL數據庫上完美的作品更改php mysql到php mssql
<?php
// visit http://php.net/pdo for more details
// start error handling
try
{
// connect
$pdo = new PDO('mysql:host=localhost;dbname=name', 'name', 'password');
// enable error handling through exceptions
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// create safe query
$query = $pdo->prepare("SELECT ip FROM tester WHERE state = ? ORDER BY RAND
(UNIX_TIMESTAMP(NOW())) LIMIT 1");
// pass data & execute query (since the data are of string type
// and therefore can be passed in this lazy way)
$query->execute(array($_POST['State']));
// get value
$ip = $query->fetchColumn();
// print out the IP address using $ip
}
catch (Exception $e)
{
echo "sorry, there was an error.";
mail("[email protected]", "database error", $e->getMessage(), "From: [email protected]");
}
if(isset($_POST['email'])) {
// EDIT THE 2 LINES BELOW AS REQUIRED
$email_to = "[email protected]";
$email_subject = "This is a test";
function died($error) {
// your error code can go here
echo "We are very sorry, but there were error(s) found with the form you submitted. ";
echo "These errors appear below.<br /><br />";
echo $error."<br /><br />";
echo "Please go back and fix these errors.<br /><br />";
die();
}
// validation expected data exists
if(!isset($_POST['first_name']) ||
!isset($_POST['last_name']) ||
!isset($_POST['email']) ||
!isset($_POST['what']) ||
!isset($_POST['State']) ||
!isset($_POST['comments'])) {
died('We are sorry, but there appears to be a problem with the form you submitted.');
}
$what = $_POST['what']; // required
$first_name = $_POST['first_name']; // required
$last_name = $_POST['last_name']; // required
$email_from = $_POST['email']; // required
$state = $_POST['State']; // not required
$comments = $_POST['comments']; // required
$error_message = "";
$email_exp = '/^[A-Za-z0-9._%-][email protected][A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
if(!preg_match($email_exp,$email_from)) {
$error_message .= 'The Email Address you entered does not appear to be valid.<br />';
}
$string_exp = "/^[A-Za-z .'-]+$/";
if(!preg_match($string_exp,$first_name)) {
$error_message .= 'The First Name you entered does not appear to be valid.<br />';
}
if(!preg_match($string_exp,$last_name)) {
$error_message .= 'The Last Name you entered does not appear to be valid.<br />';
}
if(strlen($comments) < 2) {
$error_message .= 'The Comments you entered do not appear to be valid.<br />';
}
if(strlen($error_message) > 0) {
died($error_message);
}
$email_message = "Form details below.\n\n";
function clean_string($string) {
$bad = array("content-type","bcc:","to:","cc:","href");
return str_replace($bad,"",$string);
}
$email_message .= "First Name: ".clean_string($first_name)."\n";
$email_message .= "Last Name: ".clean_string($last_name)."\n";
$email_message .= "What: ".clean_string($what)."\n";
$email_message .= "Email: ".clean_string($email_from)."\n";
$email_message .= "State: ".clean_string($ip)."\n";
$email_message .= "Comments: ".clean_string($comments)."\n";
// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n" .
'X-Mailer: PHP/' . phpversion();
if (!mail($email_to, $email_subject, $email_message, $headers))
{
echo "failed to send message";
}
?>
<!-- include your own success html here -->
Thank you for contacting us. We will be in touch with you very soon.
<?php
}
?>
當有人選擇的狀態並提交網頁表單，該代碼連接到MySQL數據庫和
隨機選擇一個IP地址，並將其發送到我的電子郵件。這十分完美。
的問題我已經是我做這行的人並不想使用MySQL數據庫，所以希望它
在MSSQL數據庫intergrated。
我知道在PHP代碼上面我連接到MySQL數據庫，而不是MSSQL數據庫，但
不能制定出什麼需要改變，使這一切工作。
我確實發現了這個在線，並認爲我可能能夠與我現有的代碼進行整合，但到目前爲止沒有運氣。
<?php
$myServer = "localhost";
$myUser = "your_name";
$myPass = "your_password";
$myDB = "examples";
//connection to the database
$dbhandle = mssql_connect($myServer, $myUser, $myPass)
or die("Couldn't connect to SQL Server on $myServer");
//select a database to work with
$selected = mssql_select_db($myDB, $dbhandle)
or die("Couldn't open database $myDB");
//declare the SQL statement that will query the database
$query = "SELECT id, name, year ";
$query .= "FROM cars ";
$query .= "WHERE name='BMW'";
//execute the SQL query and return records
$result = mssql_query($query);
$numRows = mssql_num_rows($result);
echo "<h1>" . $numRows . " Row" . ($numRows == 1 ? "" : "s") . " Returned </h1>";
//display the results
while($row = mssql_fetch_array($result))
{
echo "<li>" . $row["id"] . $row["name"] . $row["year"] . "</li>";
}
//close the connection
mssql_close($dbhandle);
?>
任何幫助獲得這項工作將不勝感激。謝謝大家
阿里
你用mysql的功能。你應該調整它們。 （蘭特是MySQL，而不是SQL） – Bram
你可以發佈你正在得到的任何錯誤？您收到 – danielrsmith
後的錯誤，並表示這是指向該行觸發錯誤，所以我們可以看得更遠 – Nonym