-1
我的程序旨在搜索數據庫中輸入的特定名稱,然後程序將只顯示特定名稱的行。但是,我的代碼無法顯示特定的數據。我嘗試過很多種方法,但無法解決我的問題。我的PHP代碼如下:如何在Android Studio中僅顯示數據庫中選定的數據
<?php
$con = mysql_connect('mysql17.000webhost.com', 'a2634311_minzhe', 'MZRules0118');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("a2634311_gdp", $con);
$result = mysql_query("SELECT * FROM groupdesign");
while($row = mysql_fetch_assoc($result))
{
$output[]=$row;
}
print(json_encode($output));
mysql_close($con);
?>
我的活動代碼如下:
import android.app.Activity;
import android.content.Context;
import android.content.Intent;
import android.content.SharedPreferences;
import android.os.AsyncTask;
import android.os.StrictMode;
import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import android.widget.Button;
import android.widget.ListView;
import android.widget.TextView;
import android.widget.Toast;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import java.io.InputStream;
public class PatientLocation extends ActionBarActivity {
private ListView PatientLocationListView;
@Override
protected void onCreate(Bundle savedInstanceState) {
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
this.PatientLocationListView = (ListView) this.findViewById(R.id.listView4);
new Location().execute(new API_Connector());
}
public void setListAdapter(JSONArray jsonArray) {
SharedPreferences settings = getSharedPreferences("myprefrences", Context.MODE_PRIVATE);
String name = settings.getString("name", "");
this.PatientLocationListView.setAdapter(new PatientAdapter(jsonArray,name, this));
}
private class Location extends AsyncTask<API_Connector, Long, JSONArray> {
@Override
protected JSONArray doInBackground(API_Connector... params) {
//it is executed on Background thread
return params[0].GetPatientLocation();
}
@Override
protected void onPostExecute(JSONArray jsonArray) {
// check for null
if (jsonArray != null) {
// only pass the array to adapter if it is not null
setListAdapter(jsonArray);
} else {
Toast.makeText(PatientLocation.this, "Null Array returned", Toast.LENGTH_SHORT).show();
}
}
}
}
class PatientAdapter extends BaseAdapter {
private JSONArray dataArray;
private Activity activity;
String pname;
private static LayoutInflater inflater = null;
public PatientAdapter(JSONArray jsonArray, String name, Activity a) {
this.dataArray = jsonArray;
this.activity = a;
this.pname = name;
inflater = (LayoutInflater) this.activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
}
@Override
public int getCount() {
return this.dataArray.length();
}
@Override
public Object getItem(int position) {
return position;
}
@Override
public long getItemId(int position) {
return position;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
String patientname,patientlocation;
//set up convert view if it is null
ListCell cell = new ListCell();
if (convertView == null) {
convertView = inflater.inflate(R.layout.activity_position, null);
cell.patient_name = (TextView) convertView.findViewById(R.id.textView30);
cell.patient_location = (TextView) convertView.findViewById(R.id.textView31);
convertView.setTag(cell);
}
else {
cell = (ListCell) convertView.getTag();
}
//change the data of the cell
try {
for(int i=0;i<dataArray.length();i++) {
JSONObject jsonObject = this.dataArray.getJSONObject(i);
if(pname == jsonObject.getString("Name")) {
patientname = jsonObject.getString("Name");
patientlocation = jsonObject.getString("Location");
cell.patient_name.setText(patientname);
cell.patient_location.setText(patientlocation);
}
}
}
catch (JSONException e) {
e.printStackTrace();
}
return convertView;
}
private class ListCell {
private TextView patient_name;
private TextView patient_location;
}
}
當使用'AsyncTask'時,不需要使用'StrictMode.ThreadPolicy'方法,並且您從服務器獲取數據? –
好的,謝謝你的信息。是的,我從服務器獲取數據 – Elzy
看來,在View類中,當我刪除if情況時,它將顯示來自服務器的所有數據。但是,如果是這種情況,則無法顯示任何內容。 – Elzy