PHP/MYSQL UPDATE在數據庫中顯示0

-1

更新過程的工作，但該領域的一個不更新{那麼它的更新，但是當我檢查數據庫就顯示爲0，我無法找出什麼是代碼中的問題}

任何幫助會很好。

問題其member_id。

member_id其在數據庫中的int數據類型。

更新代碼

if (isset($_POST['submitted'])) 
{ 
$plan_id=$_POST['plan_id']; 
$member_id=$_POST['member_id']; 
$trainer_id=$_POST['trainer_id']; 
$exercise_id=$_POST['exercise_id']; 
$Set=$_POST['Set']; 
$weight=$_POST['weight']; 
$comment=$_POST['comment']; 
$memberadd="No"; 
$query = "UPDATE gym_plan SET "; 
$query.= "exercise_id = {$exercise_id}, "; 
$query.= "exercise_set = '{$Set}', "; 
$query.= "trainer_id = {$trainer_id}, "; 
$query.= "member_id = {$member_id}, "; 
$query.= "comment = '{$comment}', "; 
$query.= "member_id = '{$memberadd}', "; 
$query.= "weight = '{$weight}' "; 
$query.= "WHERE plan_id = {$plan_id}; "; 
$result = mysql_query($query, $connect); 
echo 'my SQL query is: '.$query; 
echo "<br/>"; 
if ($result) 
    { 
     //header("Location:editex.php"); 
$message2="The Exercise Has Been Updated"; 
$_SESSION['edit-ex']=$message2; 
    }// to check if the query run then show this message 
else 
    { 
    die(mysql_error()); 
    } 
}

和完整的代碼

<?php 
session_start(); 
$message2=""; 
require_once("db_connection.php"); 
$id = $_SESSION['staff_id']; 
if (isset($_SESSION ['username'])) 
{ 
    if($_SESSION['access_level']==3) 
    { 
    $message= "welcome, ".$_SESSION['username']." !<br/>"; 
    } 
    else 
    { 
     header("Location:index.php"); 
     $goaway="You Don't Have Privilege To Check This Page"; 
     $_SESSION['noway']=$goaway; 
    } 

} 
else 
{ 
header("Location:index.php"); 
} 
if(isset($_GET['edit'])) 
{ 
     $id2 = $_GET['edit']; 
     $member_id=$_SESSION['member_id']; 
     $query= mysql_query("SELECT * FROM gym_plan WHERE member_id='$member_id' AND exercise_id='$id2'"); 
} 
if (isset($_POST['submitted'])) 
{ 
$plan_id=$_POST['plan_id']; 
$member_id=$_POST['member_id']; 
$trainer_id=$_POST['trainer_id']; 
$exercise_id=$_POST['exercise_id']; 
$Set=$_POST['Set']; 
$weight=$_POST['weight']; 
$comment=$_POST['comment']; 
$memberadd="No"; 
$query = "UPDATE gym_plan SET "; 
$query.= "exercise_id = {$exercise_id}, "; 
$query.= "exercise_set = '{$Set}', "; 
$query.= "trainer_id = {$trainer_id}, "; 
$query.= "member_id = {$member_id}, "; 
$query.= "comment = '{$comment}', "; 
$query.= "member_id = '{$memberadd}', "; 
$query.= "weight = '{$weight}' "; 
$query.= "WHERE plan_id = {$plan_id}; "; 
$result = mysql_query($query, $connect); 
echo 'my SQL query is: '.$query; 
echo "<br/>"; 
if ($result) 
    { 
     //header("Location:editex.php"); 
$message2="The Exercise Has Been Updated"; 
$_SESSION['edit-ex']=$message2; 
    }// to check if the query run then show this message 
else 
    { 
    die(mysql_error()); 
    } 
} 

?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> 
<title>Untitled Document</title> 
</head> 

<body> 
<?php 
$br="<br/>"; 
while ($row=mysql_fetch_array($query)) 
{ 
    extract($row); 
    //echo $plan_id; 
    //echo $br; 
    //echo $exercise_id; 
    //echo $br; 
    //echo $exercise_set; 
    echo $br; 
    $query2=mysql_query("SELECT * FROM exercise WHERE exercise_id='$exercise_id'"); 
    while ($row2=mysql_fetch_array($query2)) 
    { 
     extract ($row2); 
     //echo $exercise_name; 
    } 
} 
?> 

Exercise Name : <?php echo $exercise_name;?> 
<form name="form1" method="post" action="edit-ex.php"> 
<input type="hidden" name="submitted" value="true"/> 
<input type="hidden" name="plan_id" value="<?php echo $plan_id?>"/> 
<input type="text" name="member_id" value="<?php echo $member_id;?>"/> 
<input type="hidden" name="exercise_id" value="<?php echo $exercise_id;?>"/> 
<input type="hidden" name="trainer_id" value="<?php echo $trainer_id;?>"/> 
<p>Set: <input name="Set" type="text" /><br/></p> 
<p>Weight: <input type="text" name="weight" /><br/></p> 
<p>Comment: <input type="text" name="comment" /><br/></p> 
<input type="submit" value ="Update The <?php echo $exercise_name;?>"/> 
</form> 
</body> 
</html>

來源

2014-04-19 user3314766

您不能發佈較少的代碼嗎？你不能再縮小它了嗎？ –

您的問題是在這條線：

$query.= "member_id = '{$memberadd}', ";

你在同一個查詢更新member_id到2個值，第二值$memberadd沒有設定所以它是0。

好這一行：

$query.= "member_id = {$member_id}, ";

壞在這條線：

$query.= "member_id = '{$memberadd}', ";

邊注：應停止使用mysql_ *功能，因爲這些都是過時。退房mysqli或PDO

來源

2014-04-19 21:55:49 CodeBird

非常感謝您的幫助 – user3314766

嘗試單引號（「「」）添加到田間地頭，

$query = "UPDATE gym_plan SET "; 
    $query.= "'exercise_id' = {$exercise_id}, "; 
    $query.= "'exercise_set' = '{$Set}', "; 
    $query.= "'trainer_id' = {$trainer_id}, "; 
    $query.= "'member_id' = {$member_id}, "; 
    $query.= "'comment' = '{$comment}', "; 
    $query.= "'member_id' = '{$memberadd}', "; 
    $query.= "'weight' = '{$weight}' ";

或檢查出這link

來源

2014-04-19 21:50:09 Rorschach

PHP/MYSQL UPDATE在數據庫中顯示0

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