只使用1 for循環

Question

是有可能這樣做，他們使用之後只有一個for循環，而不是2：

int index = ws.getLastRowNum() + 1; 
List<AdditiveList> list=new ArrayList<>(); 

for(int i=1; i<index; i++){ 
     list.add(new AdditiveList()); 
} 

for(AdditiveList x: list){ 
     Row row=null; 
     if (rowIterator.hasNext()) 
      row=rowIterator.next(); 
     x.inputAdditiveData(row); 
     x.outputData(); 
} 

Answer 1

我認爲這是可能的。

試試這個 -

int index=ws.getLastRowNum()+1; 
List<AdditiveList> list=new ArrayList<>(); 
for(int i=1; i<index; i++){ 
    AdditiveList additiveList = new AdditiveList(); 
    Row row = null; 
    if(rowIterator.hasNext()) 
     row = rowIterator.next(); 
    additiveList.inputAdditiveData(row); 
    additiveList.outputData(); 
    list.add(additiveList); 
} 

---

如果rowIterator.hasNext()返回false，在這種情況下，名單將增加空值。如果這是正確的不按照要求，那麼你應該省略像下面的零 -

for(int i=1; i<index; i++){ 
    if(rowIterator.hasNext()){ 
     Row row = rowIterator.next(); 
     AdditiveList additiveList = new AdditiveList(); 
     additiveList.inputAdditiveData(row); 
     additiveList.outputData(); 
     list.add(additiveList); 
    }   
}