2009-07-11 116 views
0

我有這個IBAction是假設在屏幕上跳轉的一個字符,但是當它調用它只是將字符向上移動一次,然後每次調用後字符只是越來越多地下移。這個功能應該被調用,然後角色會'跳'起來,然後直接從屏幕上掉下來,因爲我沒有與地面發生任何碰撞。任何建議爲什麼發生這種情況?蒂姆是我的UIImageView的名稱,持有chracater,順便說一句。Iphone,objective-c如何爲平臺遊戲製作跳躍方法

-(IBAction)Jump:(id)sender 

int jumpSpeed = JumpSpeedLimit; CGPoint newCenter = tim.center;

if(!mainJumping){ 
    //then start jumping 
    mainJumping = TRUE; 
    jumpSpeed = JumpSpeedLimit*-1; 
    newCenter.x -= jumpSpeed; 
    tim.center = newCenter; 

} else { 
    //then continue jumping if already in the air 
    //crazy math that I won't explain 
    if(jumpSpeed < 0){ 
     jumpSpeed *= 1 - JumpSpeedLimit/75; 
     if(jumpSpeed > -JumpSpeedLimit/5){ 
      jumpSpeed *= -1; 
     } 
    } 
    if(jumpSpeed > 0 && jumpSpeed <= JumpSpeedLimit){ 
     jumpSpeed *= 1 + JumpSpeedLimit/50; 
    } 
    newCenter = tim.center; 
    newCenter.x -= jumpSpeed; 
    tim.center = newCenter; 
    /* 
    //if hits the floor, then stop jumping 

    if(tim.center.x >= 360 - tim.bounds.size.height){ 
     mainJumping = FALSE;    
     newCenter = tim.center; 
     newCenter.x = 360 - tim.bounds.size.height; 
     tim.center = newCenter; 
    }*/ 

} 

}

回答

1

你壓根設計這個錯誤。您希望按下「跳轉」按鈕設置某種標誌,然後在您的遊戲引擎代碼中處理該標誌。