Oracle在值後選擇最大記錄

Question

我有這樣的表。我必須找到最大日期（max_date_6）no ='000000001 001'和狀態= 6。以及狀態= 1的日期（max_date_1），該日期在max_date_6之後。我寫這樣的查詢，但它只給出兩個狀態的最大值。但max_date_6必須是20943和MAX_DATE_1必須是21002

WITH max_date_6 AS 
(
     SELECT no, 
        Max(DATE) date_6 
     FROM  TABLE 
     where status=6 
     AND  no='00000001 001' 
     GROUP BY no), max_date_1 AS 
(
     SELECT no, 
        max(DATE) date_1 
     FROM  TABLE 
     WHERE status=1 
     AND  no='00000001 001' 
     GROUP BY no) 
SELECT date_6, 
     date_1 
FROM max_date_6, 
     max_date_1 where date_6<=date_1 

Answer 1

沒有必要讓這裏的東西複雜化，你只需要兩個MAX與情況的：

SELECT Max(case when status = 6 then DATE end) as date_6, 
     Max(case when status = 1 then DATE end) as date_1 
FROM TABLE 
where no='00000001 001' 

編輯的版本，現在需要date_1> max（date_6），表示如果沒有date_1> max（date_6），則返回null，否則返回與前面相同的結果。

SELECT Max(case when status = 6 then DATE end) as date_6, 
     (select Max(DATE) 
     from TABLE 
     where status = 1 
      and no = t1.no 
      and date > (select max(date) from TABLE 
         where no = t1.no 
         and status = 6)) as date_1 
FROM TABLE t1 
where no = '00000001 001' 

Answer 2

所以，如果你前面的那一行想爲status=6和date爲status=1最大date。 這是不可能的，除非你有一些順序收集行。出於這個原因，我添加了列ID（也許你有一些其他的密鑰，但隱藏它）。 所以輸入數據是：

NO    TDATE STATUS ID 
----------------- ----- ------ -- 
00000001 001 21223  1 1 
00000001 001 21041  1 2 
00000001 001 21002  1 3 
00000001 001 20943  6 4 
00000001 001 20939  6 5 
00000001 001 20933  1 6 
00000001 001 20943  6 7 

查詢和結果：

with t001 as (select * from input where no = '00000001 001'), 
t6 as (select * 
    from (select id, tdate from t001 where status = 6 
    order by tdate desc, id) 
    where rownum = 1) 
select t6.tdate max_date_6, t001.tdate max_date_1 
    from t6, t001 
    where t001.id = (
    select max(id) from t001 where status = 1 and id<t6.id) 

result: 
MAX_DATE_6 MAX_DATE_1 
---------- ---------- 
    20943  21002 

Answer 3

鑑於你預期的數據，TT聽起來像你想的最低日期狀態= 1，其中該日期大於的最大日期狀態= 6

WITH m6 AS (
    SELECT max(tdate) AS max_date_6 
     FROM mytable 
     WHERE status = 6 
     AND no = '00000001 001' 
) 
SELECT min(m1.tdate) AS max_date_1, m6.max_date_6 
    FROM mytable m1, m6 
WHERE m1.status = 1 
    AND m1.no = '00000001 001' 
    AND m1.tdate > m6.max_date_6; 

可替換地：

WITH m6 AS (
    SELECT no, max(tdate) AS max_date_6 
     FROM mytable 
     WHERE status = 6 
     GROUP BY no 
) 
SELECT min(m1.tdate) AS max_date_1, m6.max_date_6 
    FROM mytable m1 INNER JOIN m6 
    ON m1.no = m6.no 
    AND m1.tdate > m6.max_date_6 
WHERE m1.status = 1 
    AND m1.no = '00000001 001';