獲得前兩名（切片？）中field1的從爆炸和場2

Question

myTable 

field1 | field2 
------------------------ 
47  | 46,43,22,88,99,12 
22  | 12,99 
88  | 77 
12  | 99,22,84,5 

算使用PHP正在尋找從我的分貝（mysql的5.x的）拉從字段1具有在FIELD2最值2倍的值。這是Joomla/JomSocial，如果它很重要，但任何答覆非常感謝。

The out put of the following query should be 
Top Member ID = 47 
Top Member ID = 12 

我都試過，但沒有happend：

$query = 'SELECT * FROM myTable; 

    $db->setQuery($query); 
    $row = $db->loadObjectList();   
    $counted = array_count_values($row[field2]); 
    arsort($counted); 
    $top_two = array_slice($counted, 0, 2); 
    foreach ($top_two as $data) 
     { 
      echo "Top Member ID = " . $data ."<BR />"; 
     } 

非常感謝您

Answer 1

可以在直SQL做到這一點：

SELECT field1, field2, LENGTH(field2)-LENGTH(REPLACE(field2,',','')) AS num FROM myTABLE ORDER BY num DESC LIMIT 2; 

的2行返回意志是你想要的。