SQL服務器 - 獲取值的總和範圍

Question

我有一個表的值是這樣的：

Date(in YMD)   Column1  Column2 
2013-08-08    0    6 
2013-08-08    1    87 
2013-08-08    2.8    23 
2013-08-08    3.87   12 
2013-08-08    0.111   65 
2013-08-08    5    98 
2013-08-08    7.876   67 
2013-08-09    4.32   8 
2013-08-09    4    2 
2013-08-09    76.05   100 
2013-08-09    32    9 

我想在列1的範圍COLUMN2的總和（即增加其落在列1列2值範圍）。所以結果會是這樣的：

[0-1]    158 
[1-2]    0 
[2-3]    23 
[3-4]    14 
[4-5]    106 
[5-6]    0 
[6-7]    0 
[7-8]    67 
[8-9]    0 
[10+]    109 

最初我得到這個結果與下面的查詢，它工作正常。

 SELECT [Range], [TotalSum] FROM 
      (
       SELECT 
        CASE WHEN Column1 >= 0 AND Column1 <= 1 THEN '[0-1]' 
         WHEN Column1 > 1 AND Column1 <= 2 THEN '[1-2]' 
         WHEN Column1 > 2 AND Column1 <= 3 THEN '[2-3]' 
         WHEN Column1 > 3 AND Column1 <= 4 THEN '[3-4]'    
         WHEN Column1 > 4 AND Column1 <= 5 THEN '[4-5]' 
         WHEN Column1 > 5 AND Column1 <= 6 THEN '[5-6]' 
         WHEN Column1 > 6 AND Column1 <= 7 THEN '[6-7]' 
         WHEN Column1 > 7 AND Column1 <= 8 THEN '[7-8]' 
         WHEN Column1 > 8 AND Column1 <= 9 THEN '[8-9]' 
         WHEN Column1 > 9 AND Column1 <= 10 THEN '[9-10]'         
         ELSE '[10+]' END [Range], 
         SUM(Column2) [TotalSum] 
       FROM dbo.table  
       GROUP BY 
        CASE WHEN Column1 >= 0 AND Column1 <= 1 THEN '[0-1]' 
         WHEN Column1 > 1 AND Column1 <= 2 THEN '[1-2]' 
         WHEN Column1 > 2 AND Column1 <= 3 THEN '[2-3]' 
         WHEN Column1 > 3 AND Column1 <= 4 THEN '[3-4]' 
         WHEN Column1 > 4 AND Column1 <= 5 THEN '[4-5]' 
         WHEN Column1 > 5 AND Column1 <= 6 THEN '[5-6]' 
         WHEN Column1 > 6 AND Column1 <= 7 THEN '[6-7]' 
         WHEN Column1 > 7 AND Column1 <= 8 THEN '[7-8]' 
         WHEN Column1 > 8 AND Column1 <= 9 THEN '[8-9]' 
         WHEN Column1 > 9 AND Column1 <= 10 THEN '[9-10]'     
         ELSE '[10+]' END 
      ) t1  
      ORDER BY 
      CASE [Range] 
         WHEN '[0-1]' THEN 0 
         WHEN '[1-2]' THEN 1 
         WHEN '[2-3]' THEN 2 
         WHEN '[3-4]' THEN 3 
         WHEN '[4-5]' THEN 4 
         WHEN '[5-6]' THEN 5 
         WHEN '[6-7]' THEN 6 
         WHEN '[7-8]' THEN 7 
         WHEN '[8-9]' THEN 8 
         WHEN '[9-10]' THEN 9     
         WHEN '[10+]' THEN 10 
      END 

現在我有一個要求，在那裏我有應用過濾器，這裏如說「凡之間‘2013年8月9日’和‘2013年8月9日’日期」 雖然這返回正確的值，但只適用於數據可用的範圍，即[3-4]，[4-5]和[10+]

請你可以建議是否有一種方法來獲取所有範圍並在TotalSum中顯示0列中沒有該行的行。

我應該在這個查詢中做什麼改變，以顯示TotalSum列中值的所有範圍值（它應該是0或該範圍的column2的總和）。

如果您有任何其他想法來實現此目的，請提出建議。任何幫助將非常感激。

Answer 1

with cte as (
    select 0 as rng_start, 1 as rng_end 
    union all 
    select 
     rng_end as rng_start, 
     case when rng_end = 10 then null else rng_end + 1 end as rng_end 
    from cte 
    where rng_end <= 10 
), cte2 as (
    select 
     '[' + cast(c.rng_start as nvarchar(max)) + 
     isnull('-' + cast(c.rng_end as nvarchar(max)), '+') + ']' as rng_str, 
     case when c.rng_start = 0 then -1 else c.rng_start end as rng_start, 
     c.rng_end 
    from cte as c 
) 
select 
    c.rng_str, 
    isnull(sum(t.column2), 0) 
from cte2 as c 
    left outer join Table1 as t on 
     t.column1 > c.rng_start and 
     (t.column1 <= c.rng_end or c.rng_end is null) and 
     t.[Date] between '2013-08-09' and '2013-08-09' 
group by c.rng_str, c.rng_start 
order by c.rng_start 

sql fiddle demo