如何在Java（Android Studio）中將整數轉換爲十進制格式？

Question

我想將我的兩個答案text1和text2轉換爲十進制格式。這怎麼可能？

int number1, number2, answer, answer2; 
EditText edit1 = (EditText)findViewById(R.id.aNum); 
EditText edit2 = (EditText)findViewById(R.id.bNum); 
TextView text1 = (TextView)findViewById(R.id.answerNum); 
TextView text2 = (TextView)findViewById(R.id.answerNum2); 
number1 = Integer.parseInt(edit1.getText().toString()); 
number2 = Integer.parseInt(edit2.getText().toString()); 
answer = (number2/(number1 * 1000)) * 60; 
answer2 = answer/60; 
text1.setText(Integer.toString(answer)); 
text2.setText(Integer.toString(answer2)); 

Answer 1

您可以使用BigDecimal：

即：

new BigDecimal(theInputString); 

Answer 2

的第一個問題是整數全是數字，也就是沒有小數位，所以如果你有：

int a = 3; 
int b = 2; 
int result = a/b; 

結果將是1而不是1.5。如果您需要保留浮點值，則將它們轉換爲double或float。然後，您可以使用String.format正確顯示該值：

text1.setText(String.format("%.2f",answer)); 

這將顯示答案到小數點後兩位。

Answer 3

使用float變量類型，而不是int和float而不是Integer類類：

float number1, number2, answer, answer2 
EditText edit1 = (EditText)findViewById(R.id.aNum); 
EditText edit2 = (EditText)findViewById(R.id.bNum); 
TextView text1 = (TextView)findViewById(R.id.answerNum); 
TextView text2 = (TextView)findViewById(R.id.answerNum2); 
number1 = Float.parseFloat(edit1.getText().toString()); 
number2 = Float.parseFloat(edit1.getText().toString()); 
answer = (number2/(number1 * 1000)) * 60; 
answer2 = answer/60; 
text1.setText(Float.toString(answer)); 
text2.setText(Float.toString(answer2));