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在SQL +中,我創建了2個表來存儲數據,1個表來交叉引用它們。目標是能夠編寫一個單獨的查詢,告訴我哪輛車在哪個經銷店,哪個經銷商提供哪輛車等。問題是,當我查詢任何東西時,每輛車都在每個經銷商中。如何正確地將2個SQL表與參考錶鏈接起來
drop table car_dealer;
drop table car;
drop table dealer;
create table dealer(
did NUMBER PRIMARY KEY,
dname VARCHAR2(20)
);
create table car(
cid NUMBER PRIMARY KEY,
cname VARCHAR2(20)
);
create table car_dealer(
cid NUMBER REFERENCES car(cid),
did NUMBER REFERENCES dealer(did),
CONSTRAINT pk_car_dealer PRIMARY KEY (cid,did)
);
INSERT INTO car
VALUES (1,'Buick Skylark');
INSERT INTO car
VALUES (2,'H2 Hummer');
INSERT INTO car
VALUES (3,'Chevy Suburban');
INSERT INTO car
VALUES (4,'BMW Z3');
INSERT INTO car
VALUES (5,'BMW 328i');
INSERT INTO car
VALUES (6,'Jeep Wrangler');
INSERT INTO car
VALUES (7,'Ford Focus');
INSERT INTO car
VALUES (8,'Range Rover');
INSERT INTO car
VALUES (9,'Toyota Supra');
INSERT INTO car
VALUES (10,'Ferrari Testarosa');
INSERT INTO car
VALUES (11,'Jaguar X12');
INSERT INTO car
VALUES (12,'Ford Fairmont');
INSERT INTO dealer
VALUES (100,'Midnight Movers');
INSERT INTO dealer
VALUES (200,'Bubbas Imports');
INSERT INTO dealer
VALUES (300,'Import Motors');
INSERT INTO car_dealer (cid,did)
VALUES (1,100);
INSERT INTO car_dealer (cid,did)
VALUES (2,100);
INSERT INTO car_dealer (cid,did)
VALUES (3,100);
INSERT INTO car_dealer (cid,did)
VALUES (4,100);
INSERT INTO car_dealer (cid,did)
VALUES (5,100);
INSERT INTO car_dealer (cid,did)
VALUES (6,100);
INSERT INTO car_dealer (cid,did)
VALUES (1,200);
INSERT INTO car_dealer (cid,did)
VALUES (2,200);
INSERT INTO car_dealer (cid,did)
VALUES (3,200);
INSERT INTO car_dealer (cid,did)
VALUES (4,200);
INSERT INTO car_dealer (cid,did)
VALUES (5,200);
INSERT INTO car_dealer (cid,did)
VALUES (6,200);
INSERT INTO car_dealer (cid,did)
VALUES (7,300);
INSERT INTO car_dealer (cid,did)
VALUES (8,300);
INSERT INTO car_dealer (cid,did)
VALUES (9,300);
INSERT INTO car_dealer (cid,did)
VALUES (10,300);
INSERT INTO car_dealer (cid,did)
VALUES (11,300);
INSERT INTO car_dealer (cid,did)
VALUES (12,300);
select dname,
cname
from dealer,car
where did = 200;
select dname,
cname
from dealer,car
where cid = 4;
午夜搬家公司(100)和布巴的進口(200)都應該只有1-6轎車和進口汽車(300)應該有車7-12只。相反,所有經銷商都擁有所有的汽車,我希望能找出一些幫助來找出原因。
,完美的工作,謝謝。 – Codarus