PHP OOP調用一般功能eachtime

Question

我通過這個

public static function CSS() { 

     $filenames = array(
      "css/tableStyles.css"=>"function1()", 
      "css/resetCSS.css"=> "function2()" 
     ); 
     foreach ($filenames as $filename=>$method){ 
      CSS::$method; 
     } 


    } 

    public function1(){ 
//do something 
    } 


    public function2(){ 
//do something else 
    } 

} 

我得到一個運行時錯誤嘗試循環。 任何提示？

編輯： 感謝arxanas，

答案是：

$filenames = array(
       "css/tableStyles.css"=>"function1", 
       "css/resetCSS.css"=> "function2" 
      ); 
      foreach ($filenames as $filename=>$method){ 
       CSS::$method(); 
      } 

Answer 1

是否CSS::function1甚至還存在？你沒有顯示它。無論如何，你不應該在你有function1()的地方有括號。相反使用

$filenames = array(
    "css/tableStyles.css"=>"function1", 
    "css/resetCSS.css"=> "function2" 
); 
foreach ($filenames as $filename=>$method){ 
    CSS::$method(); 
} 

Answer 2

您需要將function1和function2定義爲靜態。

public static function1(){ 
//do something 
    } 


    public static function2(){ 
//do something else 
    } 

Answer 3

您不能從靜態方法調用非靜態方法。您需要像靜態方法那樣定義function1和function2。而且你也稱財產不是方法。

public static function CSS() { 

     $filenames = array(
      "css/tableStyles.css"=>"function1()", 
      "css/resetCSS.css"=> "function2()" 
     ); 
     foreach ($filenames as $filename=>$method){ 
      CSS::$method(); 
     } 


    } 

    public static function1(){ 
//do something 
    } 


    public static function2(){ 
//do something else 
    } 

}