錯誤程序，而我的Android應用程序連接到服務器mysqlite

Question

錯誤：

Fatal error: Call to a member function query() on a non object in ....Rrgister.php on line 9

我Register.php文件

<?php 
require "conn.php"; 
$name=$_POST["name"]; 
$surname=$_POST["surname"]; 
$age=$_POST["age"]; 
$user_name=$_POST["user_name"]; 
$user_pass=$_POST["password"]; 
$mysql_qry="insert into candidates(name,surname,age,user_name,user_pass) values('$name','$surname','$age','$user_name','$user_pass')"; 
if($conn->query($mysql_qry)=== TRUE){ 
    echo "Insert Successfull"; 
} 
else 
{ 
    echo "Error".$mysql_qry."<br>".$conn->error; 
} 
$conn->close(); 
?> 

我conn.php

<?php 
    $db_name="candidates"; 
    $mysql_username="user"; 
    $mysql_password="password"; 
    $server_name="........."; 
    $conn = mysqli_connect($server_name, $mysql_username, $mysql_password,$db_name); 
?> 

Answer 1

如果你使用結構連接，你應該使用：

1.

$result = mysqli_query($conn, "Your query"); 

如果使用對象連接則：

2.

$conn->query("Your query"); 

看來你的程序連接，以嘗試第一個例子，讀 - http://php.net/manual/en/mysqli.query.php