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我創建了一個活動來測試從我的應用程序連接到WAMP服務器。但目前它似乎沒有工作。從android應用程序連接到服務器的問題?
活動應該在連接到服務器並單擊按鈕後更改屏幕上的文本框。但目前它不會改變。
下面的代碼有錯誤嗎?注意:我在Logcat中看不到任何錯誤,並且服務器日誌不顯示連接。
服務器類:
public class Server {
// Declared Constants
public static final String SERVER_URL = "http://192.168.56.1/androidtest.php"; //need to change?
/**
* Gets the bit of text to set
* @return A string containing the text to set
*/
public static String getTextToSet() {
/*
* Let's construct the query string. It should be a key/value pair. In
* this case, we just need to specify the command, so no additional
* arguments are needed.
*/
String data = "command=" + URLEncoder.encode("getTextToSet");
return executeHttpRequest(data);
}
/**
* Helper function used to communicate with the server by sending/receiving
* POST commands.
* @param data String representing the command and (possibly) arguments.
* @return String response from the server.
*/
private static String executeHttpRequest(String data) {
String result = "";
try {
URL url = new URL(SERVER_URL);
URLConnection connection = url.openConnection();
/*
* We need to make sure we specify that we want to provide input and
* get output from this connection. We also want to disable caching,
* so that we get the most up-to-date result. And, we need to
* specify the correct content type for our data.
*/
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
//connection.setRequestProperty("Content -Type", "textback.php");
//connection.setRequestProperty("Value1", "Value2");
// Send the POST data
DataOutputStream dataOut = new DataOutputStream(connection.getOutputStream());
dataOut.writeBytes(data);
dataOut.flush();
dataOut.close();
// get the response from the server and store it in result
DataInputStream dataIn = new DataInputStream(connection.getInputStream());
String inputLine;
while ((inputLine = dataIn.readLine()) != null) {
result += inputLine;
}
dataIn.close();
} catch (IOException e) {
/*
* In case of an error, we're going to return a null String. This
* can be changed to a specific error message format if the client
* wants to do some error handling. For our simple app, we're just
* going to use the null to communicate a general error in
* retrieving the data.
*/
e.printStackTrace();
result = null;
}
return result;
}
}
連接到服務器類:
public class ConnectToServer extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.connecttoserver);
final String textToSetAs = null;
TextView tv = (TextView) findViewById(R.id.text_to_set);
// Call the task to set the text on screen
Button setText = (Button) findViewById(R.id.button_to_set_text);
setText.setOnClickListener(new OnClickListener()
{
@Override
public void onClick(View v) {
(new GetTextTask()).execute();
}
});
}
/**
// * Used to spawn a thread to retrieve the animal sound?
*/
@SuppressWarnings("unchecked")
private class GetTextTask extends AsyncTask {
/**
* Let's make the http request and return the result as a String.
*/
protected String doInBackground(Object... args) {
// Return the server call to get the text to set
return Server.getTextToSet();
}
/**
* Display the result as a Toast.
*/
protected void onPostExecute(Object objResult) {
// check to make sure we're dealing with a string
/*
* if (objResult != null && objResult instanceof String) { String
* result = (String) objResult;
* Toast.makeText(getApplicationContext(), result,
* Toast.LENGTH_SHORT).show(); }
*/
TextView tv = (TextView) findViewById(R.id.text_to_set);
tv.setText((CharSequence) objResult);
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
}
PHP腳本:
<?php
echo "Did it work?";
// get the command
$command = $_REQUEST['command'];
// determine which command will be run
if($command == "getTextToSet") {
// return the text to set
echo "This is what you wanted back?";
} else {
echo "";
}
?>
爲什麼不嘗試使用調試器或僅使用'Log.d(..)'進行調試?檢查是否到達AsyncTask'doInBackground',然後檢查結果是否返回到'onPostExecute'。在'executeHttpRequest'中檢查服務器的確切響應。另外,請檢查IP是否正確,並且您的設備已連接到正確的無線網絡。對於模擬器,你可以嘗試'localhost',雖然沒有保證。 – Marius
您是否嘗試將您的網址粘貼到瀏覽器中以測試連接? – scrayne
是的,我能夠使用PHP腳本填充MySQL數據庫,但我似乎無法獲得與Android應用程序的任何連接!? – rossjAva2015