MySQL查詢鮮明+多

我想做這個查詢：MySQL查詢鮮明+多

SELECT * 
    FROM user k 
    INNER JOIN (
     SELECT id, tagName, b.guid, name, owner, publicKey 
     FROM noteTags a 
     INNER JOIN (
      SELECT * 
      FROM note 
      ORDER BY guid 
      LIMIT 0 , 12 
     )b ON a.guid = b.guid ORDER BY b.id DESC 
    )l ON k.owner = l.owner

但我想它返回DISTINCT b.guids。表的

結構：

note 
| 
|=id 
|=name 
|=guid 
|=owner 
|=publicKey 

noteTags 
| 
|=guid 
|=tagName 

user 
| 
|=owner 
|=username 
|=auth

基本上我想選擇所有的數據（與更深內加入限制），並返回不同的GUID

謝謝！

來源

2012-11-15 Maurício Giordano

這是一個例子，如果有兩個記錄具有相同的圖形用戶界面，下列哪一個會顯示爲'GUI = 1，Colname = 1'或'GUI = 1，Colname = 2'？ –

並不重要，兩者的值都相同 –

所以只要只顯示1個GUI，就表示以下任何一項。 –

這是我最初的回答，

SELECT * 
FROM note a 
     INNER JOIN user b 
      ON a.owner = b.owner 
     INNER JOIN notetags c 
      ON a.guid = b.guid 
     INNER JOIN 
     (
      SELECT guid, MAX(tagName) maxTag 
      FROM notetags 
      GROUP BY guid 
     ) d ON c.guid = d.guid AND 
       c.tagName = d.maxTag

來源

2012-11-15 03:49:56

如何：

SELECT *
從用戶k
INNER JOIN（
SELECT ID，標籤名，b.guid，名稱，所有者， publicKey
FROM noteTags a
INNER JOIN（
select id，name，MIN（gu ID）作爲GUID，所有者公鑰
FROM音符
GROUP BY GUID
LIMIT 0,12 ）B關於a.guid = b.guid ORDER BY b.id DESC
）升ON k.owner =升.owner

來源

2012-11-15 05:32:25

MySQL查詢鮮明+多

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