創建一個循環，繪製人三次，移動人dX dY？

Question

java代碼。林混淆這個問題

6.現在把一個循環中，吸引的人的三倍，移動他你的paintComponent方法（她？）每次 150個左右的像素（你決定多遠）

我是否需要在Jframe中創建一個掃描器來詢問用戶他或她想移動的人多少，他們只能移動該人3次？ 幫助

import javax.swing.*; 
import java.awt.*; 
import java.applet.Applet; 
public class DrawPersonPanel extends JPanel { 

private final int WIDTH = 600; 
private final int HEIGHT = 400; 
private int headX = 60; 
private int headY = 40; 
private int[] hairX = {62,75,84,85,88,90,93,99,104,110}; 
private int[] hairY = {45,46,37,38,39,30,31,32,33,54}; 
private int[] shirtX = {60,0,20,60,50,130,120,160,180,120}; 
private int[] shirtY = {100,150,180,160,250,250,160,180,150,100}; 
private int[] zigzagX = {70,75,80,85,90,95,100,105,110}; 
private int[] zigzagY = {135,140,135,140,135,140,135,140,135}; 
private int[] pantsX = {50,130,150,110,90,70,30}; 
private int[] pantsY = {250,250,375,375,300,375,375}; 


//-------------------------------------- 
// Constructor: Set up the panel. 
//-------------------------------------- 
public DrawPersonPanel() 
{ 
setPreferredSize(new Dimension(WIDTH, HEIGHT)); 
} 
//-------------------------------------- 
// Draw person 
//-------------------------------------- 
public void paintComponent (Graphics page) 
{ 
page.setColor(Color.blue); 
page.fillPolygon(shirtX, shirtY, shirtX.length); 

page.setColor(new Color(255, 228, 181)); 
page.fillOval(headX, headY, 60, 60 - 10); 


page.setColor(Color.BLACK); 
page.fillPolygon(hairX, hairY, hairX.length); 


page.setColor(Color.WHITE); 
page.drawPolyline(zigzagX, zigzagY, zigzagX.length); 


page.setColor(Color.cyan); 
page.fillPolygon(pantsX, pantsY, pantsX.length); 



} 

private void movePerson(int x, int y){ 
// Increment head. 
     headX += x; 
     headY += y; 

     for (int i = 0; i < hairX.length; i++) 
     {hairX[i] += x;} 

     for (int i = 0; i < hairY.length; i++) 
     {hairY[i] += y;} 

     // Increment shirt. 
     for (int i = 0; i < shirtX.length; i++) 
     {shirtX[i] += x;} 

     for (int i = 0; i < shirtY.length; i++) 
     {shirtY[i] += y;} 

     // Increment zig-zag on shirt. 
     for (int i = 0; i < zigzagX.length; i++) 
     {zigzagX[i] += x;} 

     for (int i = 0; i < zigzagY.length; i++) 
     {zigzagY[i] += y;} 

     // Increment pants. 
     for (int i = 0; i < pantsX.length; i++) 
     {pantsX[i] += x;} 

     for (int i = 0; i < pantsY.length; i++) 
     {pantsY[i] += y;} 


     repaint(); 

} 



} 

Answer 1

什麼問題要說的是創建一個循環調用該函數movePerson一個固定數額的3倍。他們只是說它可以是你選擇的任意數量（事先在編碼時）。