您好我正在嘗試做下面的qry，並且我不斷收到subqry總和線上的「不能有表達式中的聚合函數」錯誤。任何方式使這項工作？表達式中不能有聚合函數

SELECT ID, 
    DateColumn, 
    Contamination, 
    BrokenGlass, 
    OtherReasons, 
    SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons) AS Total, 
    SUM(Contamination)/Total AS Expr1, 
    (SELECT SUM(Contamination)/ SUM(SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons)) 
    FROM tbltest T2 
    WHERE T2.ID <= T2.ID) AS RunningSum 
FROM tbltest 
GROUP BY ID, DateColumn, Contamination, BrokenGlass, OtherReasons

來源

2012-08-08 user1342164

你不能這樣做'SUM（SUM（'這樣 – bfavaretto 2012-08-08 14:10:48

和警惕這種狀況：？'WHERE T2.ID <= T2.ID' – 2012-08-08 14:12:08

什麼是歐嘗試做你已經有'SUM + SUM ...'，那麼爲什麼外層的'SUM'？ – bfavaretto 2012-08-08 14:12:10

SELECT ID, 
    DateColumn, 
    Contamination, 
    BrokenGlass, 
    OtherReasons, 
    SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons) AS Total, 
    SUM(Contamination)/Total AS Expr1, 

    /* CHANGED THIS LINE */ 
    (SELECT SUM(Contamination)/ (SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons)) 
    FROM tbltest T2 
    WHERE T2.ID <= T2.ID) AS RunningSum 

FROM tbltest 
GROUP BY ID, DateColumn, Contamination, BrokenGlass, OtherReasons

編輯

結果是不正確是比原先要求一個完全不同的問題，我將不得不採取在黑暗中刺在這一點，因爲我什麼都不知道你的項目，但在這裏，你可能會讓你開始朝正確的方向發展。

SELECT ID, 
    DateColumn, 
    Contamination, 
    BrokenGlass, 
    OtherReasons, 
    SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons) AS Total, 
    SUM(Contamination)/Total AS Expr1, 
    (
     SELECT SUM(Contamination)/ (SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons)) 
     FROM tbltest T2 
     WHERE T2.ID <= tbltest.ID 
    ) AS RunningSum 
FROM tbltest 
GROUP BY ID, DateColumn, Contamination, BrokenGlass, OtherReasons

來源

2012-08-08 14:13:20

它給我錯誤的結果每行在運行總列中爲0.588235 – user1342164 2012-08-08 14:26:31

複製了'WHERE T2.ID <= T2.ID'。應該是'WHERE T2.ID <= tbltest.ID'。 – MatBailie 2012-08-08 14:32:29

@ user1342164我編輯了我的帖子。 – 2012-08-08 14:33:45

我猜你正在使用基於Expr1的MS-Access，請嘗試以下操作。替換在查詢中Total別名使用和你不能SUM(SUM())：

SELECT ID, 
    DateColumn, 
    Contamination, 
    BrokenGlass, 
    OtherReasons, 
    SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons) AS Total, 
    SUM(Contamination)/(SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons)) AS Expr1, 
    (SELECT SUM(Contamination)/ (SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons)) 
    FROM tbltest T2 
    WHERE T2.ID <= tbltest.ID) AS RunningSum -- I think you want T2.ID <= tbltest.ID not T2.ID <= T2.ID 
FROM tbltest 
GROUP BY ID, DateColumn, Contamination, BrokenGlass, OtherReasons

來源

2012-08-08 14:12:35 Taryn

仍然沒有得到正確的結果？每行的值是.588235 – user1342164 2012-08-08 14:19:21

@ user1342164您可以使用一些示例數據編輯原始文章，然後編輯您需要的結果嗎？ – Taryn 2012-08-08 14:21:06

我需要以某種方式劃分污染物的運行總量和Total的運行總和。因此，如果污染行1 = 7和行2 = 1，總行1 = 10和行2 = 1，它將分解8/11 – user1342164 2012-08-08 14:23:38

更改sum(sum())只使用所產生的款項加法運算符：

--SUM(SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons)) 
(SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons))

此外，不要試圖引用在同一個select子句中的別名。可以使用子查詢/派生表，也可以重複「總計」所需的計算。

--SUM(Contamination)/Total AS Expr1 
SUM(Contamination)/(SUM(Contamination) + SUM(BrokenGlass) + SUM(OtherReasons))

來源

2012-08-08 14:12:50 RobB

把話說出來 - 但更快！ – 2012-08-08 14:14:12

這是給我錯誤的結果每行是0.588235在運行總列 – user1342164 2012-08-08 14:21:00

@ user1342164 - 根據我對你的問題的評論...... WHERE T2.ID <= T2.ID'？你是指'WHERE T2.ID <= tbltest.ID'？ – MatBailie 2012-08-08 14:31:35

表達式中不能有聚合函數

回答

編輯

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