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我需要製作一個程序來加密和解密用戶輸入的內容。我無法找出一種將所有字符組合成加密單詞的方式。這裏是我的代碼(我正在使用Eclipse):Java Eclipse加密故障
import java.util.Scanner;
public class Encryption
{
public static String message = "";
public static boolean hasMessage = false;
public static boolean encrypted = false;
static char a = 0;
static char b;
static int w;
static int x;
static int y;
static int z;
static int i;
public static void display()
{
System.out.println("Message: " + message + "\n");
}
public static void encrypt(String word)
{
if(!hasMessage)
{
System.out.println("No message");
// Tell the user there is no message
}
else if(encrypted)
{
System.out.println("Message is already encrypted");
// Tell the user the message is already encrypted
}
else
{
// Reset the message to blank
for (int i = 0; i < message.length(); i++) {
i = j;
``char a = message.charAt(i);
for (int j=0; j==message.length(); j++)
{
int w = (int) a * 2;
int x = (int) w + 2;
char y = (char) x;
}
}
}
=
//get char from each letter (increase char each time), cast as int
}
System.out.println(message);
encrypted = true;
// Using the parameter word, modify message
// to contain a new value following a predictable pattern
// Hint: alter each character's ASCII value by casting
// to an integer and using math operators
// Display the new message
// Set encrypted to true
}
public static void decrypt(String word)
{
if(!hasMessage)
{
System.out.println("No message");
// Tell the user there is no message
}
else if(!encrypted)
{
System.out.println("Message not encrypted");
// Tell the user the message is not encrypted
}
else
{
int a = (int) w/2;
int w = (int) x - 2;
char x = (char) y;
System.out.println(message);
// Like encrypt, but in reverse
}
}
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
int menuChoice = 0;
while(menuChoice != 4)
{
System.out.println("[1] Enter Word\n" +
"[2] Encrypt\n" +
"[3] Decrypt\n" +
"[4] Quit\n");
menuChoice = sc.nextInt();
if(menuChoice == 1)
{
System.out.println("Input message");
message = sc.next();
// prompt user to input message
// assign next word to the class-level variable message
hasMessage = true;
encrypted = false;
// set hasMessage to true
// set encrypted to false
}
else if(menuChoice == 2)
{
encrypt(message);
}
else if(menuChoice == 3)
{
decrypt(message);
}
}
}
}
有一些嚴重的問題,這個for循環:'爲(message.charAt(一); a == message.length(); a ++)' – irrelephant
真正的問題是您正在嘗試編寫自己的加密算法。別。使用已經編寫和測試的現有算法。除非你是一名真正的密碼學專家,否則你將創建一個弱(易破)的算法,並且「對我的目的來說足夠好」永遠不會。請參閱http://stackoverflow.com/q/20227/17300 –