是否可以通過它的引用來獲取函數的名稱？

Question

我有以下代碼：

function abcdef() { } 

function test($callback) { 
    // I need the function name string("abcdef") here? 
} 

test(abcdef); 

是否有可能得到測試功能中的功能的名稱？ 那麼匿名函數呢？

Answer 1

這已經被問過：How can I get the callee in PHP?

你可以得到你需要debug_backtace的信息。這裏是一個非常乾淨的功能I have found：

<?php 
/** 
* Gets the caller of the function where this function is called from 
* @param string what to return? (Leave empty to get all, or specify: "class", "function", "line", "class", etc.) - options see: http://php.net/manual/en/function.debug-backtrace.php 
*/ 
function get_caller($what = NULL) 
{ 
    $trace = debug_backtrace(); 
    $previousCall = $trace[2]; // 0 is this call, 1 is call in previous function, 2 is caller of that function 

    if(isset($what)) { 
     return $previousCall[$what]; 
    } else { 
     return $previousCall; 
    } 
} 

你（可能）使用這樣的：

<?php 
function foo($full) 
{ 
    if ($full) { 
     return var_export(get_caller(), true); 
    } else { 
     return 'foo called from ' . get_caller('function') . PHP_EOL; 
    } 
} 

function bar($full = false) 
{ 
    return foo($full); 
} 

echo bar(); 
echo PHP_EOL; 
echo bar(true); 

將返回：

foo called from bar 

array (
    'file' => '/var/www/sentinel/caller.php', 
    'line' => 31, 
    'function' => 'bar', 
    'args' => 
    array (
    0 => true, 
), 
) 

Answer 2

您可以function.name嘗試：

function abcdef() { } 

function test($callback) { 
    alert($callback.name) 
} 

test(abcdef);