語法將兩個存儲過程爲一個

Question

SELECT * 
FROM [Live].[Test] 
WHERE [_fk_RoadMapKey] = @_fk_RoadMapKey 

SELECT @TestKey = [TestKey] 
FROM [Live].[Test] 
WHERE [_fk_RoadMapKey] = @_fk_RoadMapKey 

SELECT * 
FROM [Live].[SetofTestGrades] 
WHERE [_fk_TestKey] = @TestKey 

前兩個語句中，我們可以做到讓所有的測試，因爲我們分配

SELECT * ,@TestKey = [TestKey] FROM [Live].[Test] 
    WHERE [_fk_RoadMapKey] = @_fk_RoadMapKey 

Answer 1

您不能分配數據給一個變量，並返回數據的密押同時使用SELECT語句中，如果您正在使用@TestKey可以從另一表中的值，那麼你可以跳過變量，使用加入到另一個表中獲取數據，試試這個

SELECT * 
FROM [Live].[Test] 
WHERE [_fk_RoadMapKey] = @_fk_RoadMapKey 

SELECT S.* 
FROM [Live].[SetofTestGrades] S 
INNER JOIN [Live].[Test] T ON S.[_fk_TestKey] = T.[TestKey] 
WHERE t.[_fk_RoadMapKey] = @_fk_RoadMapKey