如何將inpustream文件分配給json？

Question

DataInputStream rd = new DataInputStream(request.getInputStream()); 
JsonObject json = new JsonObject(); 

上層代碼用於服務器。服務器得到一個inpustream，我想把這個流分配給JsonObject。 我如何將這個「rd」分配給「json」？

Answer 1

轉換輸入流，以串

public static String convertStreamToString(InputStream is) throws IOException { 
     if (is != null) { 
     Writer writer = new StringWriter(); 
     char[] buffer = new char[1024]; 
     try { 
      Reader reader = new BufferedReader(new InputStreamReader(is,"UTF-8")); 
      int n; 
      while ((n = reader.read(buffer)) != -1) { 
       writer.write(buffer, 0, n); 
      } 
     } catch (Exception e) { 
      Log.getStackTraceString(e); 
     } finally { 
      is.close(); 
     } 
     return writer.toString(); 
    } else { 
     return ""; 
    } 
} 

流使用POJO類例如爲對象：

public class PageInfo { 
private String pageName; 
private String pageContent; 


public String getPageName() { 
    return pageName; 
} 

public void setPageName(String pageName) { 
    this.pageName = pageName; 
} 

public String getColorCode() { 
    return colorCode; 
} 

public void setColorCode(String colorCode) { 
    this.colorCode = colorCode; 
} 

}

映射類將字符串轉換爲對象

public Vector<PageInfo> getPageInfo(Cursor cursor) { 
    Vector<PageInfo> pageInfo = new Vector<PageInfo>(); 
    // Column Index 
    int pageContent; 


    if (cursor != null) { 

     if (cursor.moveToFirst()) { 
      do { 
       PageInfo info = new PageInfo(); 

       pageContent = cursor.getColumnIndex(TablePageInfo.PAGE_CONTENT); 
       colorCode = cursor.getColumnIndex(TablePageInfo.COLOR_CODE); 
       bookMark = cursor.getColumnIndex(TablePageInfo.BOOK_MARK); 

       info.setPageContent(cursor.getString(pageContent)); 


       pageInfo.add(info); 

      } while (cursor.moveToNext()); 
     } 

    } 
    if (cursor != null && !cursor.isClosed()) { 
     cursor.close(); 
    } 
    return pageInfo; 
} 

添加GSON J AR然後寫下面的代碼會得到任何物體，並且將返回一個完美的JSON

package common; 

import com.google.gson.Gson; 

import com.google.gson.GsonBuilder; 

//Generics is used so any class type can be passed 
public class GsonSerializer<T> { 

public T Deserialize(String json, Class classOfT) { 

Gson gn = new GsonBuilder().create(); 

return (T) gn.fromJson(json, classOfT); 

} 

public String Serialize(T object) { 

Gson gn = new GsonBuilder().create(); 

return gn.toJson(object); 

} 

} 

更多的細節，你可以參考我的博客

http://lifeasanandroiddeveloper.blogspot.kr/2011/11/how-to-serialize-and-desearilize-json.html

Answer 2

轉換爲String，然後到JSONObject。

StringWriter writer = new StringWriter(); 
IOUtils.copy(request.getInputStream(), writer, encoding); 
String theString = writer.toString(); 
JSONObject json = new JSONObject(theString); 

有關IOUtils細節看看here。

使包含IOUtils類的jar看看here