NumberFormatException的android系統，parseDouble的GeoPoint

Question

與我的Android應用

這個問題，我現在有了這個掙扎了一段時間，並通過類似的線程很多去，但從來沒有真正解決它。我沒有設法重新墜毀我自己，但我得到來自其他用戶

這裏碰撞報告是一個碰撞報告：

java.lang.NumberFormatException: - 
at org.apache.harmony.luni.util.FloatingPointParser.initialParse(FloatingPointParser.java:149) 
at org.apache.harmony.luni.util.FloatingPointParser.parseDouble(FloatingPointParser.java:281) 
at java.lang.Double.parseDouble(Double.java:318) 
at polis.koll.HelloMapView.loadallmarkers(HelloMapView.java:665) 
at polis.koll.HelloMapView.access$10(HelloMapView.java:611) 
at polis.koll.HelloMapView$6.run(HelloMapView.java:587) 
at java.lang.Thread.run(Thread.java:1027) 

這裏是我的代碼，最後線似乎是一個生成錯誤

 SAXParserFactory spf = SAXParserFactory.newInstance(); 
     SAXParser sp = spf.newSAXParser(); 
     XMLReader xr = sp.getXMLReader(); 

     /** Send URL to parse XML Tags */ 
     URL sourceUrl = new URL(
     "http://www.mysite.com/xml.php"); 

     /** Create handler to handle XML Tags (extends DefaultHandler) */ 
     MyXMLHandler myXMLHandler = new MyXMLHandler(); 
     xr.setContentHandler(myXMLHandler); 
     xr.parse(new InputSource(sourceUrl.openStream())); 
     } catch (Exception e) { 
     //System.out.println("XML Pasing Excpetion = " + e); 
     } 

     sitesList = MyXMLHandler.sitesList; 
     gotsnr = ""; 
     gotmarkers = 0; 
     LocationOverlay locationOverlay = new LocationOverlay(mapView, getResources().getDrawable(R.drawable.polis), mContext); 

     if (sitesList !=null){ 
     for (int i = 0; i < sitesList.getSnr().size(); i++) { 
     gotsnr = sitesList.getSnr().get(i); 
     gotmarkers = (i); 
     //if (gotsnr !=""){ 
     if (sitesList.getLat().get(i).equalsIgnoreCase("")||sitesList.getLat().get(i).equalsIgnoreCase(null)){ 
      // Empty, do nothing 

     } else{ 

     GeoPoint point = new GeoPoint(new Double(Double.parseDouble(sitesList.getLat().get(i)) * 1e6).intValue() , new Double(Double.parseDouble(sitesList.getLng().get(i)) * 1e6).intValue()); 

*編輯下面replie到@kcoppock

這可以做詭計嗎？

double dlat = 0; 
double dlng = 0; 

      if (sitesList.getLat().get(i) !=null && !"".equals(sitesList.getLat().get(i))){ 
        try { 
         dlat = Double.parseDouble(sitesList.getLat().get(i)); 
        } catch (NumberFormatException e) { 
         //System.out.println(e.getMessage()); 
        } 
       } 
      if (sitesList.getLng().get(i) !=null && !"".equals(sitesList.getLng().get(i))){ 
       try { 
        dlng = Double.parseDouble(sitesList.getLng().get(i)); 
       } catch (NumberFormatException e) { 
        //System.out.println(e.getMessage()); 
       } 
      } 

      if (dlat !=0 && dlng !=0){ 

      GeoPoint point = new GeoPoint(new Double(dlat * 1e6).intValue() , new Double(dlng * 1e6).intValue());  

Answer 1

你不處理擺在首位，這是即使你沒有崩潰壞習慣的NumberFormatException。將其分開排列，首先解析雙打，並確保捕捉到NumberFormatException並對其進行適當處理（例如，拋出警告對話框，放置默認值等），以防由於某種原因getLat()或getLon()中的值無法解析，這是在這些情況下顯然發生的事情。

double lat = 0, lng = 0; 
String sLat = sitesList.getLat().get(i); 
String sLng = sitesList.getLng().get(i); 
GeoPoint point; 

try { 
    lat = Double.parseDouble(sLat); 
    lng = Double.parseDouble(sLng); 

    //If it gets here, they parsed successfully 
    point = new GeoPoint((int)(lat * 1e6), (int)(lng * 1e6)); 
} catch (NumberFormatException e) { 
    Log.e("TAG", "Couldn't parse latitude and/or longitude"); 
}